/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 A personnel director for a corpo... [FREE SOLUTION] | 91Ó°ÊÓ

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A personnel director for a corporation has hired ten new engineers. If three (distinctly different) positions are open at a Cleveland plant, in how many ways can she fill the positions?

Short Answer

Expert verified
There are 720 ways to fill the positions.

Step by step solution

01

Understand the scenario

We are to determine the number of ways to assign three different positions to ten different new hires. This is a permutation problem because the order in which the positions are filled matters due to their uniqueness.
02

Identify mathematical concept

The problem is a permutation problem without repetition because we are assigning three distinct positions from a group of ten people. The formula to find the number of permutations of choosing r objects from n is given by: \[ P(n, r) = \frac{n!}{(n-r)!} \] where \( n \) is the total number of objects (10 engineers), and \( r \) is the number of objects to choose (3 positions).
03

Apply the permutation formula

Apply the formula to find the number of ways to fill the positions: \[ P(10, 3) = \frac{10!}{(10-3)!} = \frac{10!}{7!} \]
04

Calculate the factorial values

Evaluate the factorials: \( 10! = 10 \times 9 \times 8 \times 7! \), and \( 7! \) cancels out in the equation. So, we have: \[ P(10, 3) = 10 \times 9 \times 8 \]
05

Compute the final result

Multiply the numbers obtained from the factorial calculation: \( 10 \times 9 \times 8 = 720 \). Thus, there are 720 ways to fill the positions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorials
Factorials are a fundamental concept in permutations and combinatorics. A factorial, denoted by the symbol "!", is the product of an integer and all the positive integers less than it. For example, the factorial of 4, written as \(4!\), is calculated as \(4 \times 3 \times 2 \times 1 = 24\). The concept of factorials is essential because it helps in calculating permutations and combinations.

In permutations, factorials are used to compute the total number of arrangements possible. For instance, \(10!\) represents the total number of ways to arrange 10 distinct items, which equals \(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 3,628,800\). Large factorials can grow rapidly, and often in permutation problems, we use only parts of them to simplify our calculations.

Factorials are crucial for understanding the rest of our concepts as they form the backbone of the permutation formula.
Combinatorics
Combinatorics is an area of mathematics focused on counting. It's about figuring out how many ways we can choose, arrange, or combine different items from a larger group. This field includes a wide range of problems, including permutations, combinations, and more.

Permutations, a key part of combinatorics, deal with the arrangement of items. Here, order matters. For instance, assigning 3 specific jobs to 10 candidates involves permutations, as suggested in the original exercise. If the order didn't matter, we'd be dealing with combinations instead.
  • Permutations: Focus on ordered arrangements.
  • Combinations: Concern unordered selections.

Understanding combinatorics is important as it helps break down complex counting problems into simpler ones we can solve using mathematical formulas and logic.
Permutation Formula
The permutation formula is a mathematical expression used to calculate the number of ways to arrange a certain number of items from a larger collection. In simpler terms, it helps decide how many different sequences can be formed when selecting a few objects from a bigger set.

The formula for permutations when choosing \(r\) objects from \(n\) is given by: \[P(n, r) = \frac{n!}{(n-r)!}\] Here, \(n\) represents the total number of objects available, and \(r\) is the number of objects we need to arrange.

This formula takes into account that order matters. Applied to the original problem, with 10 engineers and 3 specific positions, it ensures we consider every possible order in which the positions can be filled. By applying this formula, we were able to calculate the number \(720\), showing that there are 720 different ways those three distinctly different positions can be filled from the pool of ten diverse candidates.

Using the permutation formula simplifies complex assignments and arrangements by providing a structured way to determine all possible sequences.

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Most popular questions from this chapter

In the definition of the independence of two events, you were given three equalities to check: \(P(A | B)=P(A)\) or \(P(B | A)=P(B)\) or \(P(A \cap B)=P(A) P(B)\). If any one of these equalities holds, \(A\) and \(B\) are independent. Show that if any of these equalities hold, the other two also hold.

Americans can be quite suspicious, especially when it comes to government conspiracies. On the question of whether the U.S. Air Force has withheld proof of the existence of intelligent life on other planets, the proportions of Americans with varying opinions are given in the table. $$\begin{array}{lc} \hline \text { Opinion } & \text { Proportion } \\ \hline \text { Very likely } & .24 \\ \text { Somewhat likely } & .24 \\ \text { Unlikely } & .40 \\ \text { Other } & .12 \\ \hline \end{array}$$ Suppose that one American is selected and his or her opinion is recorded. a. What are the simple events for this experiment? b. Are the simple events that you gave in part (a) all equally likely? If not, what are the probabilities that should be assigned to each? c. What is the probability that the person selected finds it at least somewhat likely that the Air Force is withholding information about intelligent life on other planets?

Suppose that we ask \(n\) randomly selected people whether they share your birthday. a. Give an expression for the probability that no one shares your birthday (ignore leap years). b. How many people do we need to select so that the probability is at least. 5 that at least one shares your birthday?

Let \(A, B,\) and \(C\) be events such that \(P(A)>P(B)\) and \(P(C)>0 .\) Construct an example to demonstrate that it is possible that \(P(A | C)

If \(A\) and \(B\) are independent events, show that \(A\) and \(\bar{B}\) are also independent. Are \(\bar{A}\) and \(\bar{B}\) independent?

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