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Show that the binomial distribution belongs to the exponential family.

Short Answer

Expert verified
Yes, the binomial distribution can be expressed in the exponential family form.

Step by step solution

01

Identifying the Binomial Distribution

The probability mass function (PMF) of a binomial distribution with parameters \(n\) and \(p\) is given by \(P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\) for \(k = 0, 1, 2, ..., n\). We need to express this PMF in the form characteristic of the exponential family.
02

Form of the Exponential Family

The exponential family of distributions takes the general form: \(f(x| heta) = h(x) \, ext{exp}( heta T(x) - A( heta))\) where \(T(x)\) is the sufficient statistic, \(\theta\) is the natural (canonical) parameter, \(A(\theta)\) is the log-partition function, and \(h(x)\) is the base measure.
03

Rewriting the Binomial PMF

Write the binomial PMF in exponential form: \(P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} = \frac{n!}{k!(n-k)!} \text{exp} \left( k \log(p) + (n-k) \log(1-p) \right)\). Identify \(T(x), \theta, A(\theta),\) and \(h(x)\).
04

Identifying the Components

Set \(\theta = \log \left( \frac{p}{1-p} \right)\), \(T(x) = k\),\ and \(A(\theta) = n \log \left( 1 + e^{\theta} \right)\). The base measure \(h(x)\) is given by \(\frac{n!}{k!(n-k)!}\), which is constant with respect to \(\theta\).
05

Verification

Verify that substituting \(\theta, T(x), A(\theta),\) and \(h(x)\) into the exponential family form reproduces the original binomial PMF.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The binomial distribution is one of the most fundamental distributions in probability theory. It describes the number of successes in a fixed number of independent Bernoulli trials. Each trial results in a success with probability \(p\) and failure with probability \(1-p\). For example, if you flip a coin 10 times, the number of heads (assuming heads is considered a success) follows a binomial distribution if the coin is fair (\(p = 0.5\)).

This distribution is characterized by two parameters: \(n\), which is the number of trials, and \(p\), the probability of a single success. Sequential trials in a binomial model assume the same probability \(p\), which makes them identically distributed. One key feature is that each trial is independent of the others, so the outcome of one trial doesn't affect another.
  • Parameters: \(n\), number of trials, \(p\), success probability.
  • Common usage: modeling yes/no outcomes over a set number of events.
  • Example: Flipping a fair coin multiple times and counting heads.
Probability Mass Function
In probability theory, the probability mass function (PMF) provides the likelihood of a discrete random variable taking a particular value. For a binomial distribution, the PMF can be expressed as:
\[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]where \(k\) is the number of successes out of \(n\) trials.

The PMF gives us a way to calculate the probability of obtaining exactly \(k\) successes in \(n\) independent trials, each with a success probability \(p\). The term \(\binom{n}{k}\) is the binomial coefficient, representing all the different ways \(k\) successes can occur in \(n\) trials. It is a fundamental probability tool for discrete distributions like the binomial distribution.
  • Purpose: Determines probability of specific outcomes.
  • Formula: Uses binomial coefficient for "combinations".
  • Example Calculation: Probability of getting 2 heads in 3 coin flips.
Sufficient Statistic
A sufficient statistic is a concept in statistics that essentially captures all the information needed about a parameter of interest from the data. In the case of the binomial distribution, the number of successes \(k\) serves as a sufficient statistic. This means that knowing \(k\) is enough to understand the likelihood of the data, without needing to know the arrangement of those successes among the trials.

For instance, if you know there were 4 successes in 10 trials, you have all necessary information about the parameter of interest \(p\). The notion here is efficiency—\(T(x) = k\) incorporates the entirety of the trials' information relevant to estimating \(p\) in a concise way.
  • Definition: Statistic capturing all data information for parameter estimation.
  • In Binomial: \(T(x) = k\), the number of successes.
  • Application: Simplifies analysis by summarizing data's essence.
Canonical Parameter
In the context of the exponential family of distributions, the canonical or natural parameter \(\theta\) is a transformed parameter that expresses the distribution in a standard form. For the binomial distribution, this natural parameter is defined as \(\theta = \log \left( \frac{p}{1-p} \right)\). This transformation relates the linear predictor \(p\), a common probability measure, to \(\theta\).

Expressing a distribution in its canonical form helps to generalize and simplify statistical modeling across various types of data. It provides consistency in how we handle different exponential family distributions, facilitating both analyses and computations in statistics.
  • Definition: Transformed parameter for standard distribution forms.
  • In Binomial: \(\theta = \log \left( \frac{p}{1-p} \right)\).
  • Advantage: Standardizes model representation, aiding simplified computations.

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Most popular questions from this chapter

In Example A of Section \(8.4,\) we used knowledge of the exact form of the sampling distribution of \(\hat{\lambda}\) to estimate its standard error by $$s_{\hat{\lambda}}=\sqrt{\frac{\hat{\lambda}}{n}}$$ This was arrived at by realizing that \(\sum X_{i}\) follows a Poisson distribution with parameter \(n \lambda_{0} .\) Now suppose we hadn't realized this but had used the bootstrap, letting the computer do our work for us by generating \(B\) samples of size \(n=23\) of Poisson random variables with parameter \(\lambda=24.9,\) forming the mle of \(\lambda\) from each sample, and then finally computing the standard deviation of the resulting collection of estimates and taking this as an estimate of the standard error of \(\hat{\lambda}\) Argue that as \(B \rightarrow \infty,\) the standard error estimated in this way will tend to \(s_{\hat{\lambda}}\).

Let the unknown probability that a basketball player makes a shot successfully be \(\theta .\) Suppose your prior on \(\theta\) is uniform on [0,1] and that she then makes two shots in a row. Assume that the outcomes of the two shots are independent. a. What is the posterior density of \(\theta ?\) b. What would you estimate the probability that she makes a third shot to be?

The exponential distribution is \(f(x ; \lambda)=\lambda e^{-\lambda x}\) and \(E(X)=\lambda^{-1} .\) The cumulative distribution function is \(F(x)=P(X \leq x)=1-e^{-\lambda x} .\) Three observations are made by an instrument that reports \(x_{1}=5\) and \(x_{2}=3,\) but \(x_{3}\) is too large for the instrument to measure and it reports only that \(x_{3}>10 .\) (The largest value the instrument can measure is \(10.0 .\) ) a. What is the likelihood function? b. What is the mle of \(\lambda ?\)

In an ecological study of the feeding behavior of birds, the number of hops between flights was counted for several birds. For the following data, (a) fit a geometric distribution, (b) find an approximate \(95 \%\) confidence interval for \(p,(c)\) examine goodness of fit. (d) If a uniform prior is used for \(p,\) what is the posterior distribution and what are the posterior mean and standard deviation? \begin{array}{cc} \hline \text { Number of Hops } & \text { Frequency } \\ \hline 1 & 48 \\ 2 & 31 \\ 3 & 20 \\ 4 & 9 \\ 5 & 6 \\ 6 & 5 \\ 7 & 4 \\ 8 & 2 \\ 9 & 1 \\ 10 & 1 \\ 11 & 2 \\ 12 & 1 \\ \hline \end{array}

Let \(X_{1}, \ldots, X_{n}\) be an i.i.d. sample from an exponential distribution with the density function $$f(x | \tau)=\frac{1}{\tau} e^{-x / \tau}, \quad 0 \leq x<\infty$$ a. Find the mle of \(\tau.\) b. What is the exact sampling distribution of the mle? c. Use the central limit theorem to find a normal approximation to the sampling distribution. d. Show that the mle is unbiased, and find its exact variance. (Hint: The sum of the \(X_{i}\) follows a gamma distribution.) e. Is there any other unbiased estimate with smaller variance? f. Find the form of an approximate confidence interval for \(\tau\) g. Find the form of an exact confidence interval for \(\tau\)

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