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Let the unknown probability that a basketball player makes a shot successfully be \(\theta .\) Suppose your prior on \(\theta\) is uniform on [0,1] and that she then makes two shots in a row. Assume that the outcomes of the two shots are independent. a. What is the posterior density of \(\theta ?\) b. What would you estimate the probability that she makes a third shot to be?

Short Answer

Expert verified
a. Posterior density: \( 3\theta^2 \). b. Probability of third shot: \( \frac{3}{4} \).

Step by step solution

01

Define Prior Distribution

The uniform prior distribution for \(\theta\) over the interval [0,1] is given by a constant distribution: \( P(\theta) = 1 \) for \(\theta \in [0,1] \), implying a non-informative prior assumption.
02

Determine Likelihood Function

Given that the basketball player made 2 successful shots out of 2, the likelihood function based on a binomial distribution is \( L(\theta) = \theta^2 \), since each shot outcome is independent.
03

Apply Bayes' Theorem

The posterior distribution is proportional to the product of the prior and likelihood: \[ P(\theta |\text{data}) \propto L(\theta) \cdot P(\theta) = \theta^2 \cdot 1 = \theta^2 \].
04

Normalize Posterior Distribution

To find the proper posterior density, normalize \(\theta^2\) over the interval [0,1]. Compute the integral: \[ \int_0^1 \theta^2 \, d\theta = \frac{\theta^3}{3} \Bigg|_0^1 = \frac{1}{3} \]. Thus, the normalized posterior density is \( P(\theta | \text{data}) = 3\theta^2 \).
05

Estimate Probability of Third Shot

The expected value of the posterior distribution gives the estimated probability of a third successful shot: \[ E[\theta] = \int_0^1 \theta \cdot 3\theta^2 \, d\theta = 3 \int_0^1 \theta^3 \, d\theta = 3 \cdot \frac{\theta^4}{4} \Bigg|_0^1 = \frac{3}{4} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Posterior Distribution
In Bayesian statistics, the concept of a posterior distribution is crucial. It represents our updated beliefs about a parameter after observing data.
Essentially, it is the final verdict on what we think the parameter might be, combining both our prior beliefs and the new evidence provided by the data. In this particular exercise, we observe a basketball player who makes two successful shots, which leads us to revise our belief about her likelihood of hitting future shots.
The prior distribution in this example was uniform, meaning no initial bias towards any probability value for her success. By applying Bayes' theorem, this prior is updated to form the posterior distribution.
Mathematically, this is represented as \( P(\theta | \text{data}) \propto \text{Likelihood} \times \text{Prior} \), and after observing the data, turned into \( P(\theta | \text{data}) = 3\theta^2 \).
This posterior distribution indicates that higher probabilities for success are more credible after the two consecutive hits.
Binomial Distribution
The binomial distribution is essential in understanding the likelihood of a basketball player's performance in making shots. It models the number of successes in a sequence of independent events, each with the same probability of success.
In this case, the player shoots twice, and both attempts result in a success. We can see each shot as a single trial with success denoted as making the basket.
The likelihood function, based on the binomial distribution, is presented as \( L(\theta) = \theta^2 \) because we need to consider her making two independent successful shots.
Assuming independence means the shots don't influence each other, so the same probability applies to every attempt.
Bayesian Inference
Bayesian inference is the process of updating probabilities based on new data. It's a core concept in Bayesian statistics. Here, you start with a prior distribution (your initial beliefs) and update these beliefs once you observe new data, through Bayes' theorem.
The main goal is to improve upon the initial guess about a parameter by integrating additional information obtained from observations.
For the basketball player, the prior was uniform on \([0,1]\), signaling equal initial belief across all possible shot probabilities. After witnessing two successful shots, Bayesian inference provides the foundation to adjust this prior to a posterior distribution \(3\theta^2\).
This exercise exemplifies how inference works to strengthen our beliefs with real data, refining predictions for future events.
Prior Distribution
A prior distribution is our initial guess about a parameter's value before observing any data, reflecting our initial beliefs and assumptions.
In this problem, the prior is uniform, meaning we consider all probabilities equally possible before watching the player shoot. This approach is termed non-informative or flat prior, as it does not favor any particular probability over another initially.
However, once new data, such as the successful shots, come into play, the prior is reevaluated to arrive at a posterior distribution.
The use of such priors is fundamental because they set the baseline from which we can update our beliefs, allowing us to ultimately compute the likelihood of future outcomes like the probability of making the next shot in this scenario.

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Most popular questions from this chapter

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Suppose that \(X_{1}, X_{2}, \ldots, X_{n}\) are i.i.d. random variables on the interval [0,1] with the density function $$f(x | \alpha)=\frac{\Gamma(2 \alpha)}{\Gamma(\alpha)^{2}}[x(1-x)]^{\alpha-1}$$ where \(\alpha>0\) is a parameter to be estimated from the sample. It can be shown that $$\begin{aligned} E(X) &=\frac{1}{2} \\ \operatorname{Var}(X) &=\frac{1}{4(2 \alpha+1)} \end{aligned}$$ a. How does the shape of the density depend on \(\alpha ?\) b. How can the method of moments be used to estimate \(\alpha ?\) c. What equation does the mle of \(\alpha\) satisfy? d. What is the asymptotic variance of the mle? e. Find a sufficient statistic for \(\alpha .\)

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