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91Ó°ÊÓ

Find the exact null distribution of the Mann-Whitney statistic, \(U_{Y},\) in the case where \(m=3\) and \(n=2\).

Short Answer

Expert verified
The null distribution of \(U_Y\) consists of possible values of \(U_Y\) calculated for ranked permutations, with corresponding frequencies.

Step by step solution

01

Understand the Problem

The Mann-Whitney statistic, also known as the Mann-Whitney U statistic, is used to test the null hypothesis that two samples come from the same distribution. We are given two samples of sizes \(m = 3\) and \(n = 2\) and need to find the exact null distribution of the Mann-Whitney statistic \(U_Y\).
02

Construct the Combined Set and Rank

Combine the sample data from both groups. Consider all possible permutations of ranking the combined set where the ranks are assigned from 1 to \(m+n=5\).
03

Calculate the Mann-Whitney Statistic for Each Permutation

For each permutation, calculate the Mann-Whitney U statistic \(U_Y\), which is the sum of the ranks for one of the groups, typically \(Y\), minus the expected minimum rank sum. The formula is \(U_Y = R_Y - \frac{n(n+1)}{2}\), where \(R_Y\) is the sum of the ranks for the group \(Y\). Since \(n = 2\), the expected minimum rank sum is 3.
04

List Possible Values of the Mann-Whitney Statistic

Compute \(U_Y\) for all permutations. List each distinct \(U_Y\) value which represents how often different sums of ranks can occur. These distinct values form the null distribution.
05

Count and Tabulate Frequencies

For each distinct \(U_Y\) value, count how many permutations result in each value. This count gives the probability (or frequency) of each \(U_Y\) value occurring under the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis is a fundamental concept in statistics, which serves as a default or starting position for statistical testing. It states that there is no significant difference between the groups being compared. In the context of the Mann-Whitney U test, the null hypothesis is that the two samples, each from their respective groups, are drawn from the same distribution. The basic assumption of the null hypothesis is an equal probability of occurrences across the groups, aiming to show that any observed differences in the sample are due to random chance rather than systematic differences.
To test this hypothesis, we compare the distributions of the two samples. If the samples indeed seem similar, we maintain the null hypothesis. However, if a statistical test shows significant differences between the samples, we reject the null hypothesis, suggesting that the samples come from different distributions.
Permutations
Permutations play a crucial role in statistical testing, especially in non-parametric tests like the Mann-Whitney U test. A permutation involves reorganizing the elements of a set into a different order. In this exercise, our task is to determine the permutations of ranks when combining two groups of samples. Given group sizes of 3 and 2 (making a total of 5 elements), we calculate every possible way to assign ranks 1 to 5 to these elements.
This process helps us list all conceivable arrangements and compute the Mann-Whitney U statistic for each. By evaluating every permutation, we grasp the scope of variability within the ranks. This is vital in establishing a null distribution, which represents what we would expect under the null hypothesis.
Rank Sum
The rank sum is the cornerstone of the Mann-Whitney U statistic creation process. In this method, we assign ranks to the combined sample data and calculate the sum of ranks for each specified group. For example, in our exercise, we combine the data from both groups and then determine their respective ranks.
Once ranked, the sum of the ranks for one group is calculated, typically called the rank sum. For calculating the Mann-Whitney U statistic, if we consider group Y, the rank sum is crucial as it forms part of the formula: \(U_Y = R_Y - \frac{n(n+1)}{2}\). Here, \(R_Y\) represents the rank sum for group Y, and the subtraction of \(\frac{n(n+1)}{2}\) accounts for the minimum expected rank sum for that group. This helps us understand how groups compare in terms of their ranked positions within the combined data set.
Null Distribution
The null distribution is a conceptual tool that visualizes the range of possible outcomes for a statistical test when the null hypothesis is true. In the Mann-Whitney U test, the null distribution is specifically the distribution of the U statistic under the assumption that both groups come from the same distribution.
The creation of a null distribution involves calculating the U statistic for all possible permutations of ranks. By noting each permutation and its corresponding U value, we build a profile of outcomes that could occur by random chance. The null distribution will give us specified probabilities (or frequencies) for each U statistic occurring if the null hypothesis holds. This allows us to assess the likelihood of our observed data and decide whether or not to reject the null hypothesis. It is a crucial aspect that aids in evaluating the statistical significance of any differences observed between the sample groups.

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Most popular questions from this chapter

A computer was used to generate four random numbers from a normal distribution with a set mean and variance: \(1.1650, .6268, .0751, .3516 .\) Five more random normal numbers with the same variance but perhaps a different mean were then generated (the mean may or may not actually be different): .3035,2.6961,1.0591 2.7971,1.2641. a. What do you think the means of the random normal number generators were? What do you think the difference of the means was? b. What do you think the variance of the random number generator was? c. What is the estimated standard error of your estimate of the difference of the means? d. Form a \(90 \%\) confidence interval for the difference of the means of the random number generators. e. In this situation, is it more appropriate to use a one-sided test or a two- sided test of the equality of the means? f. What is the \(p\) -value of a two-sided test of the null hypothesis of equal means? g. Would the hypothesis that the means were the same versus a two-sided alternative be rejected at the significance level \(\alpha=.1 ?\) h. Suppose you know that the variance of the normal distribution was \(\sigma^{2}=1\) How would your answers to the preceding questions change?

The media often present short reports of the results of experiments. To the critical reader or listener, such reports often raise more questions than they answer. Comment on possible pitfalls in the interpretation of each of the following. a. It is reported that patients whose hospital rooms have a window recover faster than those whose rooms do not. b. Nonsmoking wives whose husbands smoke have a cancer rate twice that of wives whose husbands do not smoke. c. A 2 -year study in North Carolina found that \(75 \%\) of all industrial accidents in the state happened to workers who had skipped breakfast. d. A school integration program involved busing children from minority schools to majority (primarily white) schools. Participation in the program was voluntary. It was found that the students who were bused scored lower on standardized tests than did their peers who chose not to be bused. e. When a group of students were asked to match pictures of newborns with pictures of their mothers, they were correct \(36 \%\) of the time. f. A survey found that those who drank a moderate amount of beer were healthier than those who totally abstained from alcohol. g. A 15 -year study of more than 45,000 Swedish soldiers revealed that heavy users of marijuana were six times more likely than nonusers to develop schizophrenia. h. A University of Wisconsin study showed that within 10 years of the wedding, \(38 \%\) of those who had lived together before marriage had split up, compared to \(27 \%\) of those who had married without a "trial period." i. A study of nearly 4,000 elderly North Carolinians has found that those who attended religious services every week were \(46 \%\) less likely to die over a six-year period than people who attended less often or not at all, according to researchers at Duke University Medical Center.

If \(X \sim N\left(\mu_{X}, \sigma_{X}^{2}\right)\) and \(Y\) is independent \(N\left(\mu_{Y}, \sigma_{Y}^{2}\right),\) what is \(\pi=P(X

Two independent samples are to be compared to see if there is a difference in the population means. If a total of \(m\) subjects are available for the experiment, how should this total be allocated between the two samples in order to (a) provide the shortest confidence interval for \(\mu_{X}-\mu_{Y}\) and (b) make the test of \(H_{0}: \mu_{X}=\mu_{Y}\) as powerful as possible? Assume that the observations in the two samples are normally distributed with the same variance.

Verify that the two-sample \(t\) test at level \(\alpha\) of \(H_{0}: \mu_{X}=\mu_{Y}\) versus \(H_{A}: \mu_{X} \neq \mu_{Y}\) rejects if and only if the confidence interval for \(\mu_{X}-\mu_{Y}\) does not contain zero.

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