Chapter 8: Problem 8
Explain why the Diophantine equation \(24 x_{1}-18 x_{2}+60 x_{3}=21\) has no solution.
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Chapter 8: Problem 8
Explain why the Diophantine equation \(24 x_{1}-18 x_{2}+60 x_{3}=21\) has no solution.
These are the key concepts you need to understand to accurately answer the question.
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Prove the following proposition: For all natural numbers \(m\) and \(n,\) if \(m\) and \(n\) are twin primes other than the pair 3 and \(5,\) then 36 divides \(m n+1\) and \(m n+1\) is a perfect square.
Prove the first part of Corollary 8.14 . Let \(a, b \in \mathbb{Z},\) and let \(p\) be a prime number. If \(p \mid(a b),\) then \(p \mid a\) or \(p \mid b\).
The purpose of this exercise will be to prove that the nonlinear Diophantine equation \(3 x^{2}-y^{2}=-2\) has no solution. (a) Explain why if there is a solution of the Diophantine equation \(3 x^{2}-\) \(y^{2}=-2,\) then that solution must also be a solution of the congruence \(3 x^{2}-y^{2} \equiv-2(\bmod 3)\) (b) If there is a solution to the congruence \(3 x^{2}-y^{2} \equiv-2(\bmod 3)\), explain why there then must be an integer \(y\) such that \(y^{2} \equiv 2(\bmod 3)\). (c) Use a proof by contradiction to prove that the Diophantine equation \(3 x^{2}-y^{2}=-2\) has no solution.
Use mathematical induction to prove the second part of Corollary \(8.14 .\) Let \(p\) be a prime number, let \(n \in \mathbb{N},\) and let \(a_{1}, a_{2}, \ldots, a_{n} \in \mathbb{Z}\). If \(p \mid\left(a_{1} a_{2} \cdots a_{n}\right),\) then there exists a \(k \in \mathbb{N}\) with \(1 \leq k \leq n\) such that \(p \mid a_{k}\)
Let \(a, b,\) and \(c\) be integers with \(a \neq 0\) and \(b \neq 0 .\) If \(a\) and \(b\) are relatively prime, then the linear Diophantine equation \(a x+b y=c\) has infinitely many solutions. In addition, if \(\left(x_{0}, y_{0}\right)\) is a particular solution of this equation, then all the solutions of the equation are given by $$x=x_{0}+b k \quad y=y_{0}-a k$$ where \(k \in \mathbb{Z}\).
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