Chapter 3: Problem 11
Prove that for each integer \(a\), if \(a^{2}-1\) is even, then 4 divides \(a^{2}-1\).
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Chapter 3: Problem 11
Prove that for each integer \(a\), if \(a^{2}-1\) is even, then 4 divides \(a^{2}-1\).
These are the key concepts you need to understand to accurately answer the question.
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Prove that there do not exist three consecutive natural numbers such that the cube of the largest is equal to the sum of the cubes of the other two.
(a) If an integer has a remainder of 6 when it is divided by 7 , is it possible to determine the remainder of the square of that integer when it is divided by \(7 ?\) If so, determine the remainder and prove that your answer is correct. (b) If an integer has a remainder of 11 when it is divided by 12 , is it possible to determine the remainder of the square of that integer when it is divided by \(12 ?\) If so, determine the remainder and prove that your answer is correct. (c) Let \(n\) be a natural number greater than 2. If an integer has a remainder of \(n-1\) when it is divided by \(n\), is it possible to determine the remainder of the square of that integer when it is divided by \(n ?\) If so, determine the remainder and prove that your answer is correct.
Prove the following proposition: If \(p, q \in \mathbb{Q}\) with \(p
Are the following propositions true or false? Justify each conclusion with a counterexample or a proof. (a) For all integers \(a\) and \(b\) with \(a \neq 0,\) the equation \(a x+b=0\) has a rational number solution. (b) For all integers \(a, b,\) and \(c,\) if \(a, b,\) and \(c\) are odd, then the equation \(a x^{2}+b x+c=0\) has no solution that is a rational number. Hint: Do not use the quadratic formula. Use a proof by contradiction and recall that any rational number can be written in the form \(\frac{p}{q},\) where \(p\) and \(q\) are integers, \(q>0\), and \(p\) and \(q\) have no common factor greater than \(1 .\) (c) For all integers \(a, b, c,\) and \(d,\) if \(a, b, c,\) and \(d\) are odd, then the equation \(a x^{3}+b x^{2}+c x+d=0\) has no solution that is a rational number.
For a right triangle, suppose that the hypotenuse has length \(c\) feet and the lengths of the sides are \(a\) feet and \(b\) feet. (a) What is a formula for the area of this right triangle? What is an isosceles triangle? (b) State the Pythagorean Theorem for right triangles. \(\star\) (c) Prove that the right triangle described above is an isosceles triangle if and only if the area of the right triangle is \(\frac{1}{4} c^{2}\).
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