/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 According to a local marathon cl... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

According to a local marathon club, the mean finishing time for a marathon is 274 minutes, with a standard deviation of 63 minutes. a. If I can run a marathon with a finishing time of 170 minutes, find the Z-score for my marathon time. b. Is my marathon finishing time of 170 minutes unusually fast? Explain your answer using the Z-score.

Short Answer

Expert verified
The Z-score is approximately -1.65; 170 minutes is not unusually fast.

Step by step solution

01

Understand Z-score Formula

The Z-score formula is used to find how many standard deviations an element is from the mean. It is given by the formula: \( Z = \frac{X - \mu}{\sigma} \), where \( X \) is the value, \( \mu \) is the mean, and \( \sigma \) is the standard deviation.
02

Calculate the Z-score

Using the values from the problem: \( X = 170 \) minutes, \( \mu = 274 \) minutes, and \( \sigma = 63 \) minutes, we substitute into the formula: \[ Z = \frac{170 - 274}{63} = \frac{-104}{63} \approx -1.65 \].
03

Interpret the Z-score

A Z-score of \( -1.65 \) means that the finishing time of 170 minutes is 1.65 standard deviations below the mean finishing time of 274 minutes. Typically, a Z-score of less than -2 or greater than 2 is considered unusual.
04

Determine if 170 Minutes is Unusual

Since the Z-score is approximately -1.65, which does not exceed the threshold of -2 for being unusual, a finishing time of 170 minutes is not considered unusually fast.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Standard Deviation
In statistics, the mean is a critical concept that represents the average value of a data set. It is calculated by adding up all the numbers in the data set and then dividing by the number of numbers. In our marathon example, the mean finishing time is given as 274 minutes.
  • The mean (\( \mu \)) helps us understand the central tendency of a data set, serving as a benchmark against which individual scores can be compared.
Similarly, the standard deviation is another essential concept. It measures the spread or variability of the data set around the mean. A larger standard deviation indicates a wider spread of values. For our marathon problem, the standard deviation is 63 minutes.
  • The standard deviation (\( \sigma \)) gives insight into how spread out the marathon finishing times are from the average time.
Together, the mean and standard deviation provide a comprehensive understanding of the data distribution and how typical or atypical certain values, like a marathon time, might be.
Normal Distribution
The normal distribution is a fundamental concept in statistics that describes how data points tend to cluster around a central point (the mean) and taper off symmetrically towards the extremes. This distribution is also known as a bell curve due to its shape. Most natural phenomena, including the distribution of marathon times, closely follow this pattern.
  • In a normal distribution, approximately 68% of data falls within one standard deviation from the mean, about 95% within two, and around 99.7% within three.
  • This property allows statisticians to make inferences about data, even if they haven't observed every potential data point.
  • For marathon finishing times, a normal distribution implies that most runners will finish close to the mean time (274 minutes), with fewer runners finishing much slower or much faster.
Understanding this helps us to expect certain data patterns and to better interpret the significance of deviations like extraordinarily fast marathon times.
Interpreting Z-scores
Z-scores, also known as standard scores, are a statistical tool used to determine how far or close a particular value is from the mean in terms of standard deviations. The Z-score formula is given by \( Z = \frac{X - \mu}{\sigma} \), where \( X \) is the value in question.
  • If you have a Z-score of 0, it means your value is exactly average, at the mean.
  • A positive Z-score indicates a value above the mean, while a negative Z-score indicates a value below the mean.
  • For the marathon time of 170 minutes, the Z-score of \(-1.65\) tells us the time is 1.65 standard deviations below the mean of 274 minutes.
Generally, a Z-score beyond ±2 is considered unusual since it implies the value is in the extreme 5% of the data distribution. In this case, a Z-score of \(-1.65\) doesn't reach that threshold, signaling that while running the marathon so fast is impressive, it isn't statistically rare. Understanding Z-scores offers a quantitative method for evaluating how typical or atypical a data point is within its data set.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a survey of 12 companies recruiting for recent college graduates, they reported the following numbers of job applicants per job posting: \(123,123,134,127,115,122,125,101,130,143,110,\) and 122 . a. Find the mean and standard deviation, including units. b. What is the \(Z\) score for the company with 143 job applicants per job posting?

The following table is from a sample of five hundred homes in Oregon that were asked the primary source of heating in their home. a. How many of the households heat their home with firewood? b. What percent of households heat their home with natural gas? $$ \begin{array}{|c|c|} \hline \text { Type of Heat } & \text { Relative Frequency (\%) } \\ \hline \text { Electricity } & 33 \\ \hline \text { Heating Oil } & 4 \\ \hline \text { Natural Gas } & 50 \\ \hline \text { Firewood } & 8 \\ \hline \text { Other } & 5 \\ \hline \end{array} $$

For the clinical trial of a migraine drug, subjects were randomly divided into two groups. The first received an inert pill, while the second received the test medicine. Patients were not aware of which group they were in. After one month, patients reported how many migraines they experienced. a. Which is the treatment group? b. Which is the control group (if there is one)? c. Is this study blind, double-blind, or neither? d. Is this best described as an experiment, a controlled experiment, or a placebo-controlled experiment?

Suppose a Normal distribution has a mean of \(45 \mathrm{~cm}\) and a standard deviation of \(10 \mathrm{~cm}\). a. Draw and label the Normal distribution graph. b. What is the range of data values that fall within two standard deviations of the mean? c. What percentage of the data fall between 15 and \(55 \mathrm{~cm} ?\) d. What percentage of the data fall above \(55 \mathrm{~cm} ?\)

The table below shows scores on a math test. a. Is this categorical or quantitative data? b. Make a relative frequency table for the data using a class width of 10 . c. Construct a histogram of the data. $$\begin{array}{|c|c|c|c|c|c|c|c|c|c|c|c|} \hline 82 & 55 & 51 & 97 & 73 & 79 & 100 & 60 & 71 & 85 & 78 & 59 \\ \hline 90 & 100 & 88 & 72 & 46 & 82 & 89 & 70 & 100 & 68 & 61 & 52 \\ \hline \end{array}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.