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Consider a symmetric nxnmatrix A withA2=A. Is the linear transformationT(x鈬赌)=Ax鈬赌necessarily the orthogonal projection onto a subspace ofn?

Short Answer

Expert verified

Yes, The linear transformation Tx鈬赌=Ax鈬赌is an orthogonal projection onto the subspace of nontoE1.

Step by step solution

01

Orthogonal projection:

The orthogonal projection of one vector onto another serves as the foundation for decomposing a vector into a sum of orthogonal vectors. A vector v's projection onto a second vector w is a scalar multiple of the vector w.

02

Find the linear transformation:

Here we have

v鈬赌=Av鈬赌v鈬赌=A2v鈬赌=2v鈬赌=2-2=01-=0Hence,=0and=1

Now, since the matrix A is symmetric, the eigenspaces E0andE1corresponding to the eigenvalueslocalid="1659612821751" =0and=1respectfully, are orthogonal complements. Now, =1is when the transformation T leaves the vector unchanged, and we have

E1=E0.

Also, vectors in E1are mapped to 0鈬赌by T.

Therefore, the linear transformation T(x鈬赌)=Ax鈬赌is an orthogonal projection onto the subspace of nontoE1.

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