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Among all the unit vectors u→=[xyz]in R3, find the

one for which the sum role="math" localid="1659544842303" x+2y+3z is minimal.

Short Answer

Expert verified

The vector with the minimal lengthu→=-1/14-2/14-3/14

Step by step solution

01

Step by step solution Step 1: Use Cauchy-Schwarz inequality

|v→.w→|⩽||v→||.||w→||

Observe that x+2y+3z=xyz·123so, we will takev→=123

By using the above formula we get:

role="math" localid="1659545669910" |x+2y+3z|⩽14-14⩽x+2y+3z⩽14x+2y+3z⩾-14

Also note that equality holds only and only if u→and v→are linearly dependent.

So, u→=λv→.

Thus,

u→=λ2λ3λ

02

Find the vector

Consider the equation:

x2+y2+z2=λ2+4λ2+9λ2⇒1=14λ2⇒λ2=114⇒λ=±114

Thus, the value is λ=-114 as we have to obtain vector corresponding to minimal length.

Hence, the vector with the minimal length will beu→=[-1/14-2/14-3/14]

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