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91Ó°ÊÓ

a.Consider a vectorv⊥ in Rn, and a scalar k. Show that||kv→||=|k|.||v→||

b.Show that ifv⊥ is a nonzero vector in Rn, then

u→=1||v→||is a unit vector.

Short Answer

Expert verified

(a) It is proved that, kv⊥k.v⊥.

(b) It is proved that u⊥=1.

Step by step solution

01

Consider for part (a)

Here we want to prove that given any v⊥∈Rn and for any scalar k, we have kv→=k.v⊥.

Observe the following

∥vr∥=v12+v22+……+vn2WhereVr=v1,v2,…,vn

So,

∥kv∥=kv12+kv22+….+kvn2=|k|v12+v22+…..+vn2=|k|⋅∥rr∥

02

Consider for part (b).

We will use the part (a) here to prove that u⊥=1.

Observe the following equations.

localid="1659450995384" =1vr∥r→v∥=1∥v∥⋅∥vr∥=1

Hence,

a) kv⊥=k.v⊥

b) If V is a non-zero vector in Rnthen,ur=1vris a unit vector and u⊥=1.

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