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Does the equationrank(A)=rank(ATA) holds for allnm matrices A? Explain.

Short Answer

Expert verified

The matrix B isATA-1AT .

Step by step solution

01

Determine the value of rank{A} and rank{ATA} .

Consider a nmmatrix A where kerA=vnAv=0andImA=wmAv=w.

By the Rank-Nullity theorem, the sum of the dimensions of the kernel and the image of a matrix is equal to the number of column of that matrix.

As the matrix A isnm , thenATA is annn matrix, and therefore the number of their column is the same means.

dimkerA+dimlmA=mdimkerATA+dimlmATA=m

Theorem: Dimension of the image.

For a matrix A ,dimimA=rankA .

By the theorem, the valuedimimA=rankA anddimimATA=rankATA .

SubstituterankA fordimlmA in thedimkerA+dimimA=m as follows.

dimkerA+dimimA=mrankA+dimkerA=mrankA=-dimkerA

SubstituterankATA fordimimATA in thedimkerATA+dimimATA=m as follows.

dimkerATA+dimimATA=mrankATA+dimkerATA=mrankATA=-dimkerATA

Compare the equationsrankA=m-dimkerA andrankATA=m-dimkerATA as follows.

rankA=rankATA

Hence, the equationrankA=rankATA for all nmmatrices.

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