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Give an algebraic proof for the triangle inequality

||v⇶Ä+w⇶Ä||≤||v⇶Ä||+||w⇶Ä||

Draw a sketch. Hint: Expand|v⇶Ä+w⇶Ä|2=(v⇶Ä+w⇶Ä)·(v⇶Ä+w⇶Ä)

Then use the Cauchy–Schwarz inequality.

Short Answer

Expert verified

The triangle inequality is confirmed.

Step by step solution

01

Define Cauchy–Schwarz inequality.

If x⇶Äandy⇶Äare vectors in Rnthen

|x⇶Ä·y⇶Ä|≤|x⇶Ä|·|y⇶Ä|

This statement is an equality if (and only if)x⇶Äandy⇶Äare parallel.

02

Determine the triangle inequality and draw the sketch

Use the hint:

||v⇶Ä+w⇶Ä||2=||v⇶Ä||2+||w⇶Ä||2+2v⇶Ä·w⇶Ä||v⇶Ä+w⇶Ä||2≤||v⇶Ä||2+||w⇶Ä||2+2||v⇶Ä||||w⇶Ä||||v⇶Ä+w⇶Ä||2=||v⇶Ä||+||w⇶Ä||2||v⇶Ä+w⇶Ä||2≤||v⇶Ä||+||w⇶Ä||2

The sketch for the inequality is shown below:

Thus, by taking square root of both sides, triangle inequality is confirmed.

Hence, the triangle inequality is confirmed.

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