/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q12E Find all Fourier coefficients of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find all Fourier coefficients of the absolute value function

f(t)=|t|

Short Answer

Expert verified

The Fourier coefficients are

a0=ττ2bk=0ck=-4ττk2,0

k is even.

Step by step solution

01

The Fourier coefficient of the function   f(t)=|t|

Here it needs to find out the function ft=t. Recall that the coefficients are given by

a0=ft,12bk=ft,sinktck=ft,coskt

The given function is ft=t. So,

a0=t,12=12ττ∫-ττττtdt=22ττ∫0ττtdt=ττ2

Similarly, the value of bk=ft,sinktis,

bk=t,sinktdt=1ττt,sinktdt=0

And now for the last coefficient ckconsider the solution,

ck=t,cos(kt)=1ττ∫-ττττtcos(kt)dt=2ττ∫0ττtcos(kt)dt=2ττ∫0ττtcos(kt)dt

Further solve the above expression,

ck=2ττ1ktsin(kt)0ττ-∫0π-sin(kt)dt=2ττ.1k2cos(kt)oττ=2ττk2cos(kττ)-1=-4ττk2kiseven0kiseven0

Hence, the Fourier coefficients are a0=ττ2,bk=0and ck=-4ττk2,0.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.