/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11E The angle between two nonzero el... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The angle between two nonzero elementsvandwof an inner product space is defined as

∡(v,w)=arccos<v,w>||v||.||w||

In the space [-Ï€,Ï€]with inner product

<f,g>=1π∫-ππf(t)g(t)dt

find the angle between f(t)=cos(t)and g(t)=cos(t+δ)where 0≤δ≤π. Hint: Use the formula cos(t+δ)=cos(t)cos(δ)-sin(t)sin(δ).

Short Answer

Expert verified

The angle between f and g is ∠f,g=δ.

Step by step solution

01

Integral for angles.

Consider the following conditions of integral to find the angle between f and g.

It will check three integrals.


  1. ∫-ππcos2tdt=∫-ππcos2t+12dt=12×2×∫0πcos2t+1dt=π

  2. ∫-ππcos2tdt=∫-ππ1-cos2t2dt=12×2×∫0π1-cos2t+1dt=π

  3. ∫-ππsintcostdt=∫-ππsin2t2dt=0

Now, observe the following

f,g=1π∫-ππcostcost+δdt=1π∫-ππcostcostcosδ-sintsinδdt=1Ï€cosδ∫-ππcos2tdt-sinδ∫-ππcostsintdt=1π×cosδ×π-²õ¾±²Ôδ×0=cosδ

02

Length of the functions f and g.

Also, the length of the functions f and g can be found as,

f2=f,f=1π∫-ππcos2tdt=1π×π=1g2=g,g=1π∫-ππcost+δdt=1π∫-ππcostcosδ-sin(t)sinδ2dt=cos2δ+sin2δ+0=1

Therefore, the angle between f and g

∠f,g=arccosf,gf.g=frccoscosδ=δ

Hence, the value of the angle between f and g will be

∠f,g=δ

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.