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Find the basis of all22 matrixA such thatA=[1101]=[0000], and determine its dimension.

Short Answer

Expert verified

The dimension of a basis ofA is 2 which is spanned by Span1-100,001-1.

Step by step solution

01

Determine the matrix .

Consider the equationA1101=0000where A=abcd.

Substitute the value abcdfor A in the equation A1111=0000as follows.

A1111=0000abcd1111=0000a+ba+bc+dc+d=0000

Compare the equation both side as follows.

a+b=0c+d=0

Simplify the equationa+b=0as follows.

localid="1659414423987" a+b=0a=-b

Simplify the equation c+d=0as follows.

c+d=0c=-d

Substitute the values -c for d and -a for b in the equation A=abcdas follows.

A=abcdA=a-ac-c

Therefore, the matrix A=a-ac-c.

02

Determine the basis of the matrix .

Simplify the equationA=a-ac-c as follows.

A=a-ac-cA=a-ac-c+001-1A=a1100+c001-1

Therefore, the matrix A is spanned by Span1-100,001-1where 1-100and 001-1are linear independent.

Hence, the dimension ofA is 2 and spanned by Span1-100,001-1.

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