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Question:Solve the linear system

|y+z=aX+z=bx+y=C|, where a,b andcare arbitrary constants.

Short Answer

Expert verified

Answer:

The solution of the linear system is y+z=ay+z=by+y=c,x=b+c-a2,y=a+c-b2,z=a+b-c2,

Step by step solution

01

Consider the system

Consider the linear system.

y+z=ay+z=by+y=c

The matrix form of the system is,

011|1101|b110|c

02

 Step 2: Compute the system.

Consider the matrix,

011|1101|b110|c

Perform the row reduction operation.

011|1101|b110|c~0111101b11-2c-b-a100b-a+c2010a-b+c2001a+b-c2

The values are, x=b+c-a2,y=a+c-b2,z=a+b-c2

Hence,y+z=ay+z=by+y=c, ,x=b+c-a2,y=a+c-b2,z=a+b-c2 is the solution of the linear system, .

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