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Use theorem 9.3.13 to solve the initial value problem

dx→dt=231012001x→with x→(0)=[21-1].

Hint: Find first x3(t), then x2(t), and finally x1(t).

Short Answer

Expert verified

The solution isen2-3t+t2-1+2tt

Step by step solution

01

Definition of first order linear differential equation.

Consider the differential equation f'(t)-af(t)=g(t)whereg(t)is a smooth function and 'a'is a constant. Then the general solution will bef(t)=eat∫e-atg(t)dt.

02

Determination of the solution.

Consider the differential equation as follows.

dx→dt=231012001x→A=231012001A=2f't-2ft=0

Now, the differential equation is in the form as follows.

f'(t)-af(t)=g(t), where g(t) is a smooth function, then the general solution will be as follows.

f(t)=eat∫e-atg(t)dt

03

Compute the calculation of the solution.

Substitute the value 0 for g(t) and 2 for a inf(t)=eat∫e-atg(t)dtas follows.

role="math" localid="1660805430798" f(t)=eat∫e-atg(t)dtf(t)=e2t∫e-2t×0×dtf(t)=e2t∫0×dtf(t)=e2t·C

Here C is constant

Also it can be written as follows.

C'=2-3t+t2-1+2tt

The solution ise2t2-3k+t2-1+2tt

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