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If v→is an eigenvector of A, then v→must be in the kernel of Aor in the image ofA.

Short Answer

Expert verified

The given statement is true.

Step by step solution

01

Consider the related Parameters

Assume that λ is eigenvalue of A and v→ is the eigenvector corresponding to the eigenvalue λ.

02

Determine the given statement is true or false

Two cases can be arise there.

Case I:

If λ = 0

Then, Av→ = 0 and v→∈ ker A.

Case II:

If λ ≠ 0,

Then,

A v = λv

and v→ ∈ imA

Hence, the given statement is true.

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For a given eigenvalue, find a basis of the associated eigenspace. Use the geometric multiplicities of the eigenvalues to determine whether a matrix is diagonalizable. For each of the matrices A in Exercises 1 through 20, find all (real) eigenvalues. Then find a basis of each eigenspace, and diagonalize A, if you can. Do not use technology

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