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91Ó°ÊÓ

TRUE OR FALSE

If the rank of a square matrix A is 1, then all the nonzero vectors in the image of A are eigenvectors of A.

Short Answer

Expert verified

True, all the nonzero vectors in the image of A are eigenvectors of A.

Step by step solution

01

Define eigenvector

For any scaler λ , if Av→ = λv→ , then v→ is the eigenvector of matrix A.

02

Explanation for all the nonzero vectors in the image of A are eigenvectors of A:

Maybe because linearity would allow a zero vector to be an eigenvector and allow any eigenvalue.

If rankA = 1 then , ∃ v∈ Rn,im A = span (v).

Thus, x∈ im A

Then, we have x = αv and Ax = A(αv)= βv = (β /α) αv

So, every vector in im A is an eigenvector of A.

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