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91Ó°ÊÓ

For which values of constants a, b, and c are the matrices in Exercises 40 through 50 diagonalizable?

A =[00a100010]

Short Answer

Expert verified

The A=00a100010matrix is not diagonalizable

Step by step solution

01

Characteristic equation 

Consider an n ×n matrix A and a scalar λ. Then λ is an eigenvalue5 of A.

det(A-λ±ô)=0

This is called the characteristic equation (or the secular equation) of matrix A.

02

Solution of the problem

We solve:

det(A-λl)=0-λ0a1-λ001-λ=0-λ3+a=0

The only real root of this equation is λ=a13, thus we don't have three real eigenvalues (counting their algebraic multiplicities), So A is not diagonalizable.

Therefore, the final result A is not diagonalizable.

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