/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q42E Find all the eigenvalues and 鈥... [FREE SOLUTION] | 91影视

91影视

Find all the eigenvalues and 鈥渆igenvectors鈥 of the linear transformations.

L(A)=A-AT. IsR22toR22 diagonalizable?

Short Answer

Expert verified

L is diagonalizable and the eigenvalues and eigenvectors of the given linear transformation is,

1=-2,E2=span1000,01-10,00012=0,E2=span1000,0110,0001

Step by step solution

01

Define eigenvalues

The scalar values that are associated with the vectors of the linear equations in the matrix are called eigenvalues.

Ax=x,here xis eigenvector and is the eigenvalue.

02

Use the formula and determine the possible values

Consider the given equation,

L(A)=A-AT

Solve,

LA=AA-AT=AAT=+1A

Hence, due to the entries in the main diagonal, this is only possible for1,2=-2,0

Thus, for =-2

AT=-AA=ab-bd

E2=span1000,01-10,0001

Calculate for, =0

role="math" localid="1659597245438" AT=AA=abbdE2=span1000,0110,0001

Since, L is diagonalizable.

Therefore, the eigenvalues and eigenvectors are,

1=-2,E2=span1000,01-10,00012=0,E2=span1000,0110,0001

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.