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Consider a complex n × m matrix A. TheconjugateA¯isdefined by taking the conjugate of each entry of A. For example, if

A=[2+3i52i9], thenA¯=[2-3i5-2i9]

a. Show that if A and B are complex n × p and p × m matrices, respectively, thenAB¯=A¯B¯

b. Let A be a real n × n matrixandv→+iw→ aneigenvector of A with eigenvalue p + iq. Show that the vectorv→-iw→is an eigenvector of A with eigenvalue p − iq.

Short Answer

Expert verified

a. (i,j)-th entry of =AB¯=A¯B¯=∑k=1pai,k¯⋅bk,j¯=∑k=1pai,kbk,j¯=∑k=1pai,kbk,j¯

b. v−iwis also an eigenvector of A, with the eigen value p-iq.

Step by step solution

01

Step 1:The (i , j)-th entry ofAB¯

∑k=1pai,kbk,j¯

On the other hand, the (i ,j)-the entry of is

∑k=1pai,k¯⋅bk,j¯=∑k=1pai,kbk,j¯=∑k=1pai,kbk,j¯

b.Let A be a real n × n matrixand an eigenvector of A with eigenvalue p + iq. Show that the vectoris an eigenvector of A with eigenvalue p − iq.

02

Finding eigenvector of A

Since A is a real matrix, then.A¯=A

Ifv+iu is an eigen vector of A with the eigen value,p+iq, then we have

A(v−iw)=Av+iw¯=A(v+iw)¯=(p+iq)(v+iw)¯=p+iq¯⋅v+iw¯=(p−iq)(v−iw)

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