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For a given eigenvalue, find a basis of the associated eigenspace. Use the geometric multiplicities of the eigenvalues to determine whether a matrix is diagonalizable. For each of the matrices A in Exercises 1 through 20, find all (real) eigenvalues. Then find a basis of each eigenspace, and diagonalize A, if you can. Do not use technology

12.(110011001)

Short Answer

Expert verified

The given matrix A is not a diagonalizable.

Step by step solution

01

Algebraic Versus.

Algebraic versus geometric multiplicity If λ is an eigenvalues of a square matrix A,

then gemu(1)<almu(1)

To get eigenvalues

1-λ1001-λ1001-λ-0⇒1-λ1-λ2=0⇒λ=1

02

To find the value.

A-λl=010001000for eigenbasis 100

Therefore, the matrix A is not diagonalizable.

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