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Find an eigenbasis of given matrix and diagonalize it.

A=(1326)

Short Answer

Expert verified

Eigen basis are v1=3-1andv2=12

The diagonalization of this matrix is 0700.

Step by step solution

01

Definition of diagonalizable

The matrix A is diagonalizable if there exists an eigenbasis for A. The v→1,.....,v→nis an eigenbasis for A, withAv→1=λ1v→1,...,Av→n=λnv→n, then the matrices

role="math" localid="1659532048605" S=||||v→1v→2....v→n||||androle="math" localid="1659532177343" B=λ10…00λ2…0⋮⋮⋱⋮00⋯λn

Will be diagonalize A, meaning thatS-1AS=B

02

Finding the eigenvalues of the given matrix

detA-λl=01-λ326-λ=0λ2-7λ=0λ1=0,λ2=7

03

Finding eigenvectors

For λ=0,

So the eigenvector,

v1=3-1

Forλ=7,

-632-1x2y2=02x2-y2=0

We can choose the eigenvectorv2=12.

Nowv1,v2is an eigen basis.

04

Finding the diagonizable form of the matrix

Diagonalization of this matrix is0700

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