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Show that an nxn matrixAhas at least one nonzero minor if (and only if) rank(A)n-1.

Short Answer

Expert verified

Hence, there exists at least one non-zero minor.

rank(A)n-1.

Step by step solution

01

Matrix Definition. 

Matrix is a set of numbers arrangedin rows and columns so asto form a rectangulararray.

The numbers are called the elements, or entries, of the matrix.

If there are m rows and n columns, the matrix is said to be an 鈥渕 by n鈥 matrix, written 鈥.mn

02

To show that at least one nonzero minor. 

If has at least one non-zero minor, it means that the determinant of the matrix calculated for the corresponding minor is different than 0 , which gives us at least n -1 linearly independent rows.

If A has at least n -1 linearly independent rows, then there exists an(n-1)n-1 sub matrix of A , and at least one non-zero entry of the row that was left out, hence there exists at least one non-zero minor.

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