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Find the determinants of the linear transformations in Exercises 17 through 28.

23.L(A)=ATfromnntonn

Short Answer

Expert verified

Therefore, the determinant of the linear transformations is given by,

detT=detB=(-1)n(n-1)2

Step by step solution

01

Definition. 

A determinant is a unique number associatedwith a square matrix.

A determinant is a scalar value that is a function of the entries of a square matrix.

It is the signed factor by which areas are scaled by this matrix. If the sign is negative the matrix reverses orientation.

02

Given. 

Given linear transformation,

L(A)=ATfromnntonn

03

To find determinant.

Let . A=ai,ji,jnn

We have TAji,j=(AT)ij=aij. If is the canonical basis for nn, then the matrix B=(bij)ijnnof T corresponding to has 1 on places

localid="1659521205647" (1,1),(2,n+1),(3,2n+1),...,(n-1,n2-2n+1),(n,n2-n+1),(n+1,2),(n+2,n+2),(n+3,2n+2),....,(2n-1,n2-2n),(2n,n2-n+2),(2n+1,3)(2n+2,n+3),(2n+3,2n+3),...,(3n-1,n2-2n+3),(3n,n2-n+3) .

.

.

(n2-2n+1,n-1),(n2-2n+2,2n-1),(n2-2n+3,3n-1),...,(n2-n-1,n2-n-1)((n-1)2,n2-1)(n2-n+1,n)(n2-n+2,2n),(n2-n+3+3n),..,(n2-1,(n-1)2),(n2,n2)

and 0 everywhere else. To obtain the identity matrix lnn, we clearly need

(n-1)+(n-2)+(n+3)+...+1=n(n-1)2row interchanges.

Therefore,

detT=detB=(-1)n(n-1)2

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