/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q25E Find the determinants of the lin... [FREE SOLUTION] | 91影视

91影视

Find study content
Learning Materials

Discover learning materials by subject, university or textbook.

Explanations

Textbooks
All Subjects

Anthropology

Archaeology

Architecture

Art and Design

Bengali

Biology

Business Studies

Greek

Chemistry

Chinese

Combined Science

Computer Science

Economics

Engineering

English

English Literature

Environmental Science

French

Geography

German

History

Hospitality and Tourism

Human Geography

Italian

Japanese

Law

Macroeconomics

Marketing

Math

Media Studies

Medicine

Microeconomics

Music

Nursing

Nutrition and Food Science

Physics

Polish

Politics

Psychology

Religious Studies

Sociology

Spanish

Sports Sciences

Translation

All Subjects

Biology

Business Studies

Chemistry

Combined Science

Computer Science

Economics

English

Environmental Science

Geography

History

Math

Physics

Psychology

Sociology
Features
Features

Discover all of these amazing features with a free account.

Flashcards

91影视 AI

Notes

Study Plans

Study Sets
What鈥檚 new?

Flashcards
Study your flashcards with three learning modes.

Study Sets
All of your learning materials stored in one place.

Notes
Create and edit notes or documents.

Study Plans
Organise your studies and prepare for exams.
91影视
Discover

All the hacks around your studies and career - in one place.

Find a degree

Magazine
Featured

Magazine
Trusted advice for anyone who wants to ace their studies & career.

The largest student job board with the most exciting opportunities.

Verified student deals from top brands.

Discover our mobile app to take your studies anywhere.

Learning Materials

Features

Discover

Linear Algebra With Applications

Otto Bretscher

$Math Studyset 91影视 Explanations$ Math

5th Edition 路 442 pages

ISBN: 9780321796974

Chapter 6: Q25E (page 289)

Find the determinants of the linear transformations in Exercises 17 through 28.
25. $T (M) = [\begin{matrix} 2 & 3 \\ 0 & 4 \end{matrix}]$ M from the space V of upper triangular matrices to V

Short Answer

Expert verified

Therefore, the determinant of the linear transformations is given by,

$d e t T = d e t B = 16$

Step by step solution

01

Definition.

A determinant is a unique number associatedwith a square matrix.

A determinant is a scalar value that is a function of the entries of a square matrix.

It is the signed factor by which areas are scaled by this matrix. If the sign is negative the matrix reverses orientation.

02

Given.

Given linear transformation,

$T (M) = [\begin{matrix} 2 & 3 \\ 0 & 4 \end{matrix}]$

03

To find determinant.

For $M 鈭� V$ , we have

$M = [\begin{matrix} a & b \\ 0 & d \end{matrix}]$

So we compute

$T (M) = [\begin{matrix} 2 & 3 \\ 0 & 4 \end{matrix}] M T (M) = [\begin{matrix} 2 & 3 \\ 0 & 4 \end{matrix}] [\begin{matrix} a & b \\ 0 & d \end{matrix}] T (M) = [\begin{matrix} 2 a & 2 b + 3 d \\ 0 & 4 d \end{matrix}]$

Since $B = \{E_{1, 1}, E_{1, 2}, E_{2, 2}\}$ is the canonical basis for $V$ , this means that the matrix of $T$ corresponding to $B$ is

$B = [\begin{matrix} 2 & 0 & 0 \\ 0 & 2 & 3 \\ 0 & 0 & 4 \end{matrix}]$

Therefore,

$d e T = d e t B = 16 .$

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In an economics text $^{11}$ we find the following system:

$[\begin{matrix} - R_{1} & R_{1} & - (1 - 伪) \\ 伪 & 1 - 伪 & - {(1 - 伪)}^{2} \\ R_{2} & - R_{2} & \frac{- {(1 - 伪)}^{2}}{伪} \end{matrix}] [\begin{matrix} d x_{1} \\ d y_{1} \\ d p \end{matrix}] = [\begin{matrix} 0 \\ 0 \\ - R_{2} d e_{2} \end{matrix}]$ .

Solve for $d x_{1}, d y_{1}$ , and dp. In your answer, you may refer to the determinant of the coefficient matrix as D. (You need not compute D.) The quantities $R_{1}, R_{2}$ and D are positive, and ais between zero and one. If $d e_{2}$ is positive, what can you say about the signs of $d y_{1}$ and dp?

If two $n 脳 n$ matrices A and B are similar, then the equation $d e t A = d e t B$ must hold.

For an invertiblenxnmatrix A, what is adj(adj A)?

Question: Arguing geometrically, determine whether the following orthogonal transformations from ${鈩�}^{3} to {鈩�}^{3}$ preserve or reverse orientation. See Exercise 20.
a. Reflection about a plane

b. Reflection about a line
c. Reflection about the origin

If a square matrix $A$ is invertible, then its classical adjoint $adj (A)$ is invertible as well.

See all solutions

Recommended explanations on Math Textbooks

Discrete Mathematics

Read Explanation

Geometry

Read Explanation

Applied Mathematics

Read Explanation

Decision Maths

Read Explanation

Probability and Statistics

Read Explanation

Theoretical and Mathematical Physics

Read Explanation

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.