/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q8E Question: In Exercises 5-8, find... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Question: In Exercises 5-8, find the minimal representation of the polytope defined by the inequalities \(A{\mathop{\rm x}\nolimits} \le {\mathop{\rm b}\nolimits} \) and \({\mathop{\rm x}\nolimits} \ge 0\).

8. \(A = \left( {\begin{array}{*{20}{c}}2&1\\1&1\\1&2\end{array}} \right),{\rm{ }}{\mathop{\rm b}\nolimits} = \left( {\begin{array}{*{20}{c}}8\\6\\7\end{array}} \right)\)

Short Answer

Expert verified

The minimal representation of the polytope \(P\) is \(\left\{ {\left( {\begin{array}{*{20}{c}}0\\0\end{array}} \right),\left( {\begin{array}{*{20}{c}}4\\0\end{array}} \right),\left( {\begin{array}{*{20}{c}}3\\2\end{array}} \right),\left( {\begin{array}{*{20}{c}}0\\{3.5}\end{array}} \right)} \right\}\).

Step by step solution

01

The three inequalities in \(A{\mathop{\rm x}\nolimits}  \le {\mathop{\rm b}\nolimits} \)

The three matrix inequalities \(A{\mathop{\rm x}\nolimits} \le {\mathop{\rm b}\nolimits} \) yield the following system of inequalities:

  1. \(2{x_1} + {x_2} \le 8\)
  2. \({x_1} + {x_2} \le 6\)
  3. \({x_1} + 2{x_2} \le 7\)
02

Determine the \({{\mathop{\rm x}\nolimits} _1}\)-intercept and \({{\mathop{\rm x}\nolimits} _2}\)-intercept of the three lines

The condition \({\mathop{\rm x}\nolimits} \ge 0\) places polytope \(P\) in the first quadrant of the plane. One vertex is \(\left( {0,0} \right)\).

The \({{\mathop{\rm x}\nolimits} _1}\)-intercepts\(\left( {{\mathop{\rm If}\nolimits} {x_2} = 0} \right)\) of the three lines are 4, 6, and 7, so \(\left( {4,0} \right)\) is a vertex.

The \({{\mathop{\rm x}\nolimits} _2}\)-intercepts\(\left( {{\mathop{\rm If}\nolimits} {x_1} = 0} \right)\) of the three lines are 8, 6, and 3.5, then \(\left( {0,3.5} \right)\) is a vertex.

03

Determine the intersection point corresponds to inequalities

The intersection of (a) and (b) is at \({{\mathop{\rm P}\nolimits} _{{\mathop{\rm a}\nolimits} {\mathop{\rm b}\nolimits} }} = \left( {2,4} \right)\). Testing \({{\mathop{\rm P}\nolimits} _{{\mathop{\rm ab}\nolimits} }}\) in (c) gives \(2 + 2\left( 4 \right) = 10 > 7\), so \({{\mathop{\rm P}\nolimits} _{{\mathop{\rm ab}\nolimits} }}\) is not in \({\mathop{\rm P}\nolimits} \). The intersection of (a) and (c) is at \({{\mathop{\rm P}\nolimits} _{{\mathop{\rm a}\nolimits} {\mathop{\rm c}\nolimits} }} = \left( {3,2} \right)\). Testing \({{\mathop{\rm P}\nolimits} _{{\mathop{\rm a}\nolimits} {\mathop{\rm c}\nolimits} }}\) in (b) gives \(3 + 2 = 5 < 6\). So, \({{\mathop{\rm P}\nolimits} _{{\mathop{\rm a}\nolimits} {\mathop{\rm c}\nolimits} }}\) is in \({\mathop{\rm P}\nolimits} \).

04

Determine the minimal representation of the polytope

The four vertices of the polytope are \(\left( {0,0} \right),\left( {4,0} \right)\left( {3,2} \right),\,\,{\mathop{\rm and}\nolimits} \,\,\left( {0,3.5} \right)\).

Thus, the minimal representation of the polytope \(P\) is \(\left\{ {\left( {\begin{array}{*{20}{c}}0\\0\end{array}} \right),\left( {\begin{array}{*{20}{c}}4\\0\end{array}} \right),\left( {\begin{array}{*{20}{c}}3\\2\end{array}} \right),\left( {\begin{array}{*{20}{c}}0\\{3.5}\end{array}} \right)} \right\}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: In Exercises 15-20, write a formula for a linear functional f and specify a number d, so that \(\left( {f:d} \right)\) the hyperplane H described in the exercise.

Let H be the column space of the matrix \(B = \left( {\begin{array}{*{20}{c}}{\bf{1}}&{\bf{0}}\\{ - {\bf{4}}}&{\bf{2}}\\{\bf{7}}&{ - {\bf{6}}}\end{array}} \right)\). That is, \(H = {\bf{Col}}\,B\).(Hint: How is \({\bf{Col}}\,B\) related to Nul \({B^T}\)? See section 6.1)

Question: In Exercise 6, determine whether or not each set is compact and whether or not it is convex.

6. Use the sets from Exercise 4.

Question: 2. Let Lbe the line in \({\mathbb{R}^{\bf{2}}}\) through the points \(\left( {\begin{array}{*{20}{c}}{\bf{1}}\\{\bf{4}}\end{array}} \right)\) and \(\left( {\begin{array}{*{20}{c}}{ - {\bf{2}}}\\{ - {\bf{1}}}\end{array}} \right)\). Find a linear functional f and a real number d such that \(L = \left( {f:d} \right)\).

In Exercises 21–24, a, b, and c are non-collinear points in\({\mathbb{R}^{\bf{2}}}\)and p is any other point in\({\mathbb{R}^{\bf{2}}}\). Let\(\Delta {\bf{abc}}\)denote the closed triangular region determined by a, b, and c, and let\(\Delta {\bf{pbc}}\)be the region determined by p, b, and c. For convenience, assume that a, b, and c are arranged so that\(\left[ {\begin{array}{*{20}{c}}{\overrightarrow {\bf{a}} }&{\overrightarrow {\bf{b}} }&{\overrightarrow {\bf{c}} }\end{array}} \right]\)is positive, where\(\overrightarrow {\bf{a}} \),\(\overrightarrow {\bf{b}} \) and\(\overrightarrow {\bf{c}} \)are the standard homogeneous forms for the points.

22. Let p be a point on the line through a and b. Show that\(det\left[ {\begin{array}{*{20}{c}}{\overrightarrow {\bf{a}} }&{\overrightarrow {\bf{b}} }&{\overrightarrow {\bf{p}} }\end{array}} \right] = 0\).

Question: In Exercise 5, determine whether or not each set is compact and whether or not it is convex.

5. Use the sets from Exercise 3.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.