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Determine which sets in Exercises 15-20 are bases for \({\mathbb{R}^{\bf{2}}}\) and \({\mathbb{R}^{\bf{3}}}\). Justify each answer.

\(\left[ {\begin{array}{*{20}{c}}{\bf{3}}\\{ - {\bf{8}}}\\{\bf{1}}\end{array}} \right]\), \(\left[ {\begin{array}{*{20}{c}}{\bf{6}}\\{\bf{2}}\\{ - {\bf{5}}}\end{array}} \right]\)

Short Answer

Expert verified

The vectors are not the basis for \({\mathbb{R}^3}\).

Step by step solution

01

Form a matrix using the given column vectors

\(A = \left[ {\begin{array}{*{20}{c}}3&6\\{ - 8}&2\\1&{ - 5}\end{array}} \right]\)

02

Analyze the matrix formed using the vectors

The columns of A cannot span \({\mathbb{R}^3}\) because A cannot have a pivot in every row. It means the columns are not the basis of \({\mathbb{R}^3}\).

So, the vectors are not the basis for \({\mathbb{R}^3}\).

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A useful way to test new ideas in matrix algebra, or to make conjectures, is to make calculations with matrices selected at random. Checking a property for a few matrices does not prove that the property holds in general, but it makes the property more believable. Also, if the property is actually false, you may discover this when you make a few calculations.

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