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In Exercises 5 and 6, follow the method of Examples 1 and 2 to write the solution set of the given homogeneous system in parametric vector form.

5. \(\begin{aligned}{c}{x_1} + 3{x_2} + {x_3} = 0\\ - 4{x_1} - 9{x_2} + 2{x_3} = 0\\ - 3{x_2} - 6{x_3} = 0\end{aligned}\)

Short Answer

Expert verified

The general solution in the parametric vector form is represented as \(x = {x_3}\left( {\begin{array}{*{20}{c}}5\\{ - 2}\\1\end{array}} \right)\).

Step by step solution

01

Convert the given system of equations into an augmented matrix

Anaugmented matrix for a system of equations is a matrix of numbers in which eachrowrepresents the constants from one equation, and eachcolumn represents all thecoefficients for a single variable

The augmented matrix \(\left( {\begin{array}{*{20}{c}}A&0\end{array}} \right)\) for the given system of equations \({x_1} + 3{x_2} + {x_3} = 0, - 4{x_1} - 9{x_2} + 2{x_3} = 0\) and \( - 3{x_2} - 6{x_3} = 0\) is represented as:

\(\left[ {\begin{array}{*{20}{c}}1&3&1&0\\{ - 4}&{ - 9}&2&0\\0&{ - 3}&{ - 6}&0\end{array}} \right]\)

02

Apply row operation

Perform an elementary row operation to produce the first augmented matrix.

Perform the sum of \(4\) times row 1 and row 2 at row 2.

\(\left[ {\begin{array}{*{20}{c}}1&3&1&0\\0&3&6&0\\0&{ - 3}&{ - 6}&0\end{array}} \right]\)

03

Apply row operation

Perform an elementary row operation to produce the second augmented matrix.

Perform the sum of \(1\) times row 2 and row 3 at row 3.

\(\left[ {\begin{array}{*{20}{c}}1&3&1&0\\0&3&6&0\\0&0&0&0\end{array}} \right]\)

04

Apply row operation

Perform an elementary row operationto produce the third augmented matrix.

Perform the sum of \( - 3\) times row 2 and row 1 at row 1.

\(\left[ {\begin{array}{*{20}{c}}1&0&{ - 5}&0\\0&3&6&0\\0&0&0&0\end{array}} \right]\)

05

Apply row operation

Perform an elementary row operation to produce the fourth augmented matrix.

Multiply row 2 by \(\frac{1}{3}\).

\(\left[ {\begin{array}{*{20}{c}}1&0&{ - 5}&0\\0&1&2&0\\0&0&0&0\end{array}} \right]\)

06

Convert the matrix into the equation

To obtain the solution of the system of equations, you have to convert the augmented matrix into the system of equations again.

Write the obtained matrix \(\left[ {\begin{array}{*{20}{c}}1&0&{ - 5}&0\\0&1&2&0\\0&0&0&0\end{array}} \right]\) into the equation notation.

\(\begin{array}{c}{x_1} - 5{x_3} = 0\\{x_2} + 2{x_3} = 0\end{array}\)

Thus, \({x_1} = 5{x_3},{x_2} = - 2{x_3}\), and \({x_3}\) is a free variable.

07

Determine the general solution in the parametric vector form

The general solution of \(Ax = 0\) in the parametric vector form can be represented as:

\(\begin{array}{c}x = \left[ {\begin{array}{*{20}{c}}{{x_1}}\\{{x_2}}\\{{x_3}}\end{array}} \right]\\ = \left[ {\begin{array}{*{20}{c}}{5{x_3}}\\{ - 2{x_3}}\\{{x_3}}\end{array}} \right]\\ = {x_3}\left[ {\begin{array}{*{20}{c}}5\\{ - 2}\\1\end{array}} \right]\end{array}\)

Thus, the general solution in the parametric vector form is \(x = {x_3}\left[ {\begin{array}{*{20}{c}}5\\{ - 2}\\1\end{array}} \right].\)

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Find the elementary row operation that transforms the first matrix into the second, and then find the reverse row operation that transforms the second matrix into the first.

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