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Let \(T:{\mathbb{R}^n} \to {\mathbb{R}^m}\) be a linear transformation, with A its standard matrix. Complete the following statement to make it true: 鈥T is one-to-one if and only if A has 颅颅____ pivot columns.鈥 Explain why the statement is true. [Hint:Look in the exercises for Section 1.7.]

Short Answer

Expert verified

T is one-to-one if and only if A has 颅颅\(n\) pivot columns.

Step by step solution

01

Identify the condition for the transformation of dimensions

For matrix Aof order\(m \times n\), if the vector\({\bf{x}}\)is in\({\mathbb{R}^n}\), then transformation\(T\)of vector x is represented as\(T\left( x \right)\), and it is in the dimension\({\mathbb{R}^m}\).

It can also be written as\(T:{\mathbb{R}^n} \to {\mathbb{R}^m}\).

Here, the dimension \({\mathbb{R}^n}\) is the domain, and the dimension \({\mathbb{R}^m}\) is the codomain of transformation \(T\).

02

Complete the statement to make it true

If the columns of A are linearly independent, then transformation T is one-to-one.

Matrix A has n pivot columns if they are linearly independent.

Thus, the correct statement is 鈥T is one-to-one if and only if A has 颅颅\(n\) pivot columns.鈥

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