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Question: Let \({\rm{u}}\) and \({\rm{v}}\) be the vectors shown in the figure, and suppose \({\rm{u}}\) and \({\rm{v}}\) are eigenvectors of a \(2 \times 2\) matrix A that correspond to eigenvalues 2 and 3, respectively. Let \(T:{\mathbb{R}^2} \to {\mathbb{R}^2}\) be the linear transformation given by \(T\left( x \right) = Ax\) for each \({\rm{x}}\) in \({\mathbb{R}^2}\), and let \({\rm{w}} = {\rm{u}} + {\rm{v}}\). Make a copy of the figure, and on the same coordinate system, carefully plot the vectors \(T\left( {\rm{u}} \right)\), \(T\left( {\rm{v}} \right)\), and \(T\left( {\rm{w}} \right)\).

Short Answer

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The image is given below:

Step by step solution

01

Plot \(T\left( {\rm{u}} \right) = {\rm{2u}}\)

With the help of the given figure in the exercise, draw \(2u\) because it is given that \(u\) is an eigenvector of matrix A that corresponds to eigenvalue 2.

02

Plot \(T\left( {\rm{v}} \right) = 3{\rm{v}}\)

Similarly, with the help of the given figure in the exercise, draw \(3v\) because it is given that \(u\) is an eigenvector of matrix A that corresponds to eigenvalue 3.

03

Plot \(T\left( {\rm{w}} \right)\)

It is given that \(w = u + v\), since \(T\) is linear transformation given by \(T\left( x \right) = Ax\).

So, \(T\left( w \right)\) can be obtained as follows:

\(\begin{array}{c}T\left( w \right) = T\left( {u + v} \right)\\ = A\left( {u + v} \right)\\ = A\left( u \right) + A\left( v \right)\\ = T\left( u \right) + T\left( v \right)\end{array}\)

Now, plot \(T\left( w \right) = T\left( u \right) + T\left( v \right)\) as given in the image below:

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Most popular questions from this chapter

Suppose \(A\) is diagonalizable and \(p\left( t \right)\) is the characteristic polynomial of \(A\). Define \(p\left( A \right)\) as in Exercise 5, and show that \(p\left( A \right)\) is the zero matrix. This fact, which is also true for any square matrix, is called the Cayley-Hamilton theorem.

Question: Let \(A = \left( {\begin{array}{*{20}{c}}{.5}&{.2}&{.3}\\{.3}&{.8}&{.3}\\{.2}&0&{.4}\end{array}} \right)\), \({{\rm{v}}_1} = \left( {\begin{array}{*{20}{c}}{.3}\\{.6}\\{.1}\end{array}} \right)\), \({{\rm{v}}_2} = \left( {\begin{array}{*{20}{c}}1\\{ - 3}\\2\end{array}} \right)\), \({{\rm{v}}_3} = \left( {\begin{array}{*{20}{c}}{ - 1}\\0\\1\end{array}} \right)\) and \({\rm{w}} = \left( {\begin{array}{*{20}{c}}1\\1\\1\end{array}} \right)\).

  1. Show that \({{\rm{v}}_1}\), \({{\rm{v}}_2}\), and \({{\rm{v}}_3}\) are eigenvectors of \(A\). (Note: \(A\) is the stochastic matrix studied in Example 3 of Section 4.9.)
  2. Let \({{\rm{x}}_0}\) be any vector in \({\mathbb{R}^3}\) with non-negative entries whose sum is 1. (In section 4.9, \({{\rm{x}}_0}\) was called a probability vector.) Explain why there are constants \({c_1}\), \({c_2}\), and \({c_3}\) such that \({{\rm{x}}_0} = {c_1}{{\rm{v}}_1} + {c_2}{{\rm{v}}_2} + {c_3}{{\rm{v}}_3}\). Compute \({{\rm{w}}^T}{{\rm{x}}_0}\), and deduce that \({c_1} = 1\).
  3. For \(k = 1,2, \ldots ,\) define \({{\rm{x}}_k} = {A^k}{{\rm{x}}_0}\), with \({{\rm{x}}_0}\) as in part (b). Show that \({{\rm{x}}_k} \to {{\rm{v}}_1}\) as \(k\) increases.

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(a) Find the matrix A such that [nt+1at+1]=A[ntat]

(b) Verify that [11]and [2-1] are eigenvectors of A. Find the associated eigenvalues.

(c) Find closed formulas for n(t) and a(t).

Question: Is \(\lambda = - 2\) an eigenvalue of \(\left( {\begin{array}{*{20}{c}}7&3\\3&{ - 1}\end{array}} \right)\)? Why or why not?

Let\(B = \left\{ {{{\bf{b}}_1},{{\bf{b}}_2},{{\bf{b}}_3}} \right\}\) be a basis for a vector space\(V\). Find \(T\left( {3{{\bf{b}}_1} - 4{{\bf{b}}_2}} \right)\) when \(T\) isa linear transformation from \(V\) to \(V\) whose matrix relative to \(B\) is

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