Chapter 5: Q36E (page 267)
Question: Repeat Exercise 35, assuming u and v are eigenvectors of A that correspond to eigenvalues -1 and 3, respectively.
Short Answer
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Chapter 5: Q36E (page 267)
Question: Repeat Exercise 35, assuming u and v are eigenvectors of A that correspond to eigenvalues -1 and 3, respectively.
The image is given below:

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Question: Find the characteristic polynomial and the eigenvalues of the matrices in Exercises 1-8.
7. \(\left[ {\begin{array}{*{20}{c}}5&3\\- 4&4\end{array}} \right]\)
Question: In Exercises 31 and 32, let A be the matrix of the linear transformation T. Without writing A, find an eigenvalue of A and describe the eigenspace.
31. T is the transformation on \({\mathbb{R}^2}\) that reflects points across some line through origin.
Question: Is \(\lambda = - 2\) an eigenvalue of \(\left( {\begin{array}{*{20}{c}}7&3\\3&{ - 1}\end{array}} \right)\)? Why or why not?
In Exercises 7–12, use Example 6 to list the eigenvalues of\(A\). In each case, the transformation\({\rm{x}} \mapsto A{\rm{x}}\)is the composition of a rotation and a scaling. Give the angle\(\varphi \)of the rotation, where\( - \pi < \varphi \le \pi \)and give the scale\(r\).
11.\(\left( {\begin{aligned}{}{\,\,\,.1}&{}&{.1}\\{ - .1}&{}&{.1}\end{aligned}} \right)\)
Question: A is a \({\bf{4}} \times {\bf{4}}\) matrix with three eigenvalues. One eigenspace is one-dimensional and one of the other eigenspaces is two-dimensional. Is it possible that A is not diagonalizable? Justify your answer.
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