/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Multiplying term by term, check ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Multiplying term by term, check that \((I-A)\left(I+A+A^{2}+\cdots\right)=I\). This series represents \((I-A)^{-1}\). It is nonnegative when \(A\) is nonnegative, provided it has a finite sum; the condition for that is \(\lambda_{\max }<1 .\) Add up the infinite series, and confirm that it equals \((I-A)^{-1}\), for the consumption matrix $$ A=\left[\begin{array}{lll} 0 & 1 & 1 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \end{array}\right] \quad \text { which has } \lambda_{\max }=0 $$

Short Answer

Expert verified
The identity \((I-A)(I+A) = I \) holds, confirming \((I-A)^{-1} = I + A\).

Step by step solution

01

Understanding the Series

The series \( I + A + A^2 + A^3 + \cdots \) is an infinite geometric series with the first term as the identity matrix \( I \) and common ratio \( A \). Since \( \lambda_{\max} = 0 < 1 \), we know the series converges.
02

Identify the Formula to Sum Infinite Series

The sum of an infinite series \( I + A + A^2 + \cdots \) is given by \( (I - A)^{-1} \) if the series converges. This holds when the spectral radius \( \lambda_{\max} \) of \( A \) is less than 1.
03

Verification by Direct Multiplication

We need to check that \((I-A)(I+A+A^2+\cdots) = I \). First, write the product as \((I - A)(I + A + A^2 + \cdots) = I - A + A - A^2 + A^2 - A^3 + \cdots \). Observe each successive term cancels with the next, simplifying to \(I\).
04

Sum the Infinite Series for Matrix A

Evaluate the series \( I + A + A^2 + \cdots \) using the provided matrix \( A \). Since \( A^2 = 0 \) (shown by direct multiplication) and higher powers are zero, the series simplifies to \( I + A \) since all other terms are zeros.
05

Calculate \( (I - A)^{-1} \)

Compute \( I - A \), which is \( \begin{bmatrix} 1 & -1 & -1 \ 0 & 1 & -1 \ 0 & 0 & 1 \end{bmatrix} \). Since \( A^2 = 0 \), \((I - A)(I + A) = I\), confirming \((I - A)^{-1} = I + A\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Series
A geometric series is a sum of terms where each term is a consistent multiple of the previous one. In matrices, this idea extends to adding an infinite series such as \( I + A + A^2 + A^3 + \cdots \). Here, \( I \) represents the identity matrix, and \( A \) is a square matrix. This formation is similar to a geometric series because each subsequent matrix is "multiplied" by \( A \), analogous to multiplying each subsequent term in a numeric sequence by a constant ratio.
Understanding this unique series in matrices can help solve problems involving repeated transformations or operations. When the largest eigenvalue (or the spectral radius) of \( A \) is less than 1, the geometric series converges and can be summed using a specific formula, analogous to numerical geometric series.
Mathematically, if \( \lambda_{\max} < 1 \), the infinite series converges to \( (I - A)^{-1} \). This convergence is key to simplifying complex series in matrix algebra, making it invaluable in fields like economics, engineering, and computer science.
Spectral Radius
The spectral radius of a matrix \( A \), denoted as \( \lambda_{\max} \), is the maximum of the absolute values of its eigenvalues. It is a crucial concept when discussing the convergence of matrix series. For any infinite matrix geometric series to converge, the spectral radius must be less than one.
This condition ensures the repeated multiplication of matrix \( A \) leads to diminishing terms, allowing the infinite sum to settle at a finite value. Essentially, the spectral radius offers insight into the behavior of matrices when raised to higher powers.
For example, in the given matrix \( A \), since \( A^2 = 0 \), the spectral radius is \( 0 \), confirming immediate convergence. This property can simplify complex computations, enabling us to sum potentially infinite series in practical scenarios like solving systems of linear equations, modeling economic processes, or investigating networks.
Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra where two matrices are combined to produce a new matrix. This operation follows specific rules: for two matrices \( A \) and \( B \), the element in the \( i^{th} \) row and \( j^{th} \) column of the product \( AB \) is obtained by multiplying each element of the \( i^{th} \) row of \( A \) by the corresponding element in the \( j^{th} \) column of \( B \), and summing the results.
The order of multiplication matters, as matrix multiplication is not generally commutative. That is to say, \( AB eq BA \) in most cases.
In the problem we studied, understanding matrix multiplication was crucial for verifying \( (I - A)(I + A + A^2 + \cdots) = I \). By methodically multiplying and observing cancellations between terms, we confirmed the identity matrix \( I \) as a result, showcasing the importance of structured matrix operations in solving equations.
Convergence of Series
Convergence of a series refers to whether the sum of an infinite sequence approaches a certain finite value. For matrices, this means examining repeated applications of a transformation matrix \( A \) and determining if the series of matrices \( I + A + A^2 + \cdots \) stabilizes.
The condition for convergence in matrix terms is primarily governed by the spectral radius \( \lambda_{\max} \). If \( \lambda_{\max} < 1 \), the series converges, which implies that we can find a matrix \( S \) such that \( S(I - A) = I \), or equivalently, \( S = (I - A)^{-1} \).
This is an essential concept across disciplines, particularly in ensuring stable solutions in systems influenced by consistent transformations. Understanding convergence helps mathematicians, scientists, and engineers to predict long-term behavior and solve problems that extend over potentially infinite iterations, such as in control systems, iterative algorithms, and economic models.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find a solution \(x(t), y(t)\) of the first system that gets large as \(t \rightarrow \infty\). To avoid this instability a scientist thought of exchanging the two equations! $$ \begin{array}{ll} d x / d t=0 x-4 y \\ d y / d t=-2 x+2 y \end{array} \quad \text { becomes } \quad \begin{aligned} &d y / d t=-2 x+2 y \\ &d x / d t=0 x-4 y \end{aligned} $$ Now the matrix \(\left[\begin{array}{rr}-2 & 2 \\ 0 & -4\end{array}\right]\) is stable. It has \(\lambda<0\). Comment on this craziness.

These Jordan matrices have eigenvalues \(0,0,0,0\). They have two cigenvectors (find them). But the block sizes don't match and \(J\) is not similar to \(K\) : $$ J=\left[\begin{array}{ll|ll} 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ \hline 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 \end{array}\right] \quad \text { and } \quad K=\left[\begin{array}{lll|l} 0 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 \\ \hline 0 & 0 & 0 & 0 \end{array}\right] \text {. } $$ For any matrix \(M\), compare \(J M\) with \(M K\). If they are equal, show that \(M\) is not invertible. Then \(M^{-1} J M=K\) is impossible.

$$ \text { Describe in words all matrices that are similar to }\left[\begin{array}{cc} 1 & 0 \\ 0 & -1 \end{array}\right] \text {, and find two of them. } $$

Suppose the time direction is reversed to give the matrix \(-A\) : $$ \frac{d u}{d t}=\left[\begin{array}{rr} 1 & -1 \\ -1 & 1 \end{array}\right] u \quad \text { with } \quad u_{0}=\left[\begin{array}{l} 3 \\ 1 \end{array}\right] $$ Find \(u(t)\) and show that it blows up instead of decaying as \(t \rightarrow \infty\). (Diffusion is irreversible, and the heat equation cannot run backward.)

Find the lengths and the inner product of $$ x=\left[\begin{array}{c} 2-4 i \\ 4 i \end{array}\right] \quad \text { and } \quad y=\left[\begin{array}{c} 2+4 i \\ 4 i \end{array}\right] $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.