Chapter 5: Problem 19
Every 2 by 2 matrix with trace zero can be written as $$ A=\left[\begin{array}{cc} a & b+c \\ b-c & -a \end{array}\right] $$ Show that its eigenvalues are real exactly when \(a^{2}+b^{2} \geq c^{2}\).
Short Answer
Expert verified
Eigenvalues are real when \(a^2 + b^2 \geq c^2\).
Step by step solution
01
Calculate the Eigenvalues
For a matrix \( A = \left[ \begin{array}{cc} a & b+c \ b-c & -a \end{array} \right] \), the eigenvalues can be found by solving the characteristic equation \( \text{det}(A - \lambda I) = 0 \). The determinant of \( A - \lambda I \) is \( \det\left(\begin{array}{cc} a - \lambda & b + c \ b - c & -a - \lambda \end{array}\right) \).
02
Find the Determinant
Calculating the determinant, we have: \( (a - \lambda)(-a - \lambda) - (b+c)(b-c) = \lambda^2 - a^2 - (b^2 - c^2) \). So, the characteristic polynomial is \( \lambda^2 = a^2 + b^2 - c^2 \).
03
Determine when Eigenvalues are Real
The eigenvalues \( \lambda \) are real if and only if the expression under the square root in the characteristic polynomial is non-negative. Hence, for real eigenvalues, we require \( a^2 + b^2 - c^2 \geq 0 \).
04
Conclusion
Finally, we conclude that the matrix \( A \) has real eigenvalues if and only if the inequality \( a^2 + b^2 \geq c^2 \) holds.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trace of a Matrix
In mathematics, the trace of a matrix is a simple yet important concept. The trace is the sum of the elements on the main diagonal of a square matrix. For a 2 by 2 matrix, such as \[A = \left[\begin{array}{cc} a & b+c \ b-c & -a \end{array}\right]\], The trace is calculated as follows:
- Add the top left element \(a\) and the bottom right element \(-a\).
Characteristic Equation
The characteristic equation of a matrix is a fundamental concept used to determine the eigenvalues of a matrix. This equation is derived from setting the determinant of the matrix \(A - \lambda I\) equal to zero. For our given 2 by 2 matrix, \[A = \left[\begin{array}{cc} a & b+c \ b-c & -a \end{array}\right]\]The characteristic equation is derived as follows:
- Subtract \(\lambda\) times the identity matrix from matrix \(A\):\(A - \lambda I = \left[ \begin{array}{cc} a - \lambda & b+c \ b-c & -a - \lambda \end{array} \right]\)
- Next, compute the determinant of this matrix:\[\text{det}(A - \lambda I) = (a-\lambda)(-a-\lambda) - (b+c)(b-c)\]
- Simplifying, the characteristic polynomial becomes:\[\lambda^2 = a^2 + b^2 - c^2\]
Real Eigenvalues
Eigenvalues are solutions to the characteristic equation. For a 2 by 2 matrix, whether the eigenvalues are real or complex hinges on the discriminant of the characteristic polynomial. In this context, the characteristic equation is \[\lambda^2 = a^2 + b^2 - c^2\]Eigenvalues are real when the expression under the square root, known as the discriminant, is non-negative:
- If \(a^2 + b^2 - c^2 \geq 0\), the eigenvalues are real, as we can take a real square root of a non-negative number.
- If \(a^2 + b^2 - c^2 \lt 0\), the eigenvalues would be complex as the square root of a negative number introduces the imaginary unit \(i\).
2 by 2 Matrices
Two by two matrices are the simplest type of matrices that are more complex than a single number (or a one by one matrix), yet embody many properties of larger matrices. These matrices are widely used for teaching fundamental concepts such as matrix multiplication, determinants, and eigenvalues.For a 2 by 2 matrix like \[A = \left[\begin{array}{cc} a & b+c \ b-c & -a \end{array}\right]\], they consist of four elements organized in two rows and two columns. Performing operations such as finding the determinant, trace, and eigenvalues, are relatively straightforward.
- Determinants provide insight into matrix invertibility.
- Traces help with simplifying eigenvalue calculations.
- Eigenvalues reveal fundamental properties about transformations represented by these matrices.