Chapter 2: Problem 44
Review: Which of the following are bases for \(\mathbf{R}^{3}\) ? (a) \((1,2,0)\) and \((0,1,-1)\). (b) \((1,1,-1),(2,3,4),(4,1,-1),(0,1,-1)\). (c) \((1,2,2),(-1,2,1),(0,8,0)\). (d) \((1,2,2),(-1,2,1),(0,8,6)\).
Short Answer
Expert verified
Options (c) and (d) are bases for \(\mathbf{R}^{3}\).
Step by step solution
01
Understand the Definition of a Basis
A basis of \(\mathbf{R}^{3}\) is a set of three linearly independent vectors in \(\mathbf{R}^{3}\). Each set must span \(\mathbf{R}^{3}\) and contain exactly three vectors.
02
Analyze Option (a)
Option (a) provides two vectors \((1,2,0)\) and \((0,1,-1)\). Since \(\mathbf{R}^{3}\) requires three linearly independent vectors to form a basis, option (a) cannot be a basis as it contains only two vectors.
03
Analyze Option (b)
Option (b) provides four vectors \((1,1,-1),(2,3,4),(4,1,-1),(0,1,-1)\). In \(\mathbf{R}^{3}\), a basis can only contain three vectors. Therefore, option (b) cannot be a basis because it has excess vectors beyond the required number.
04
Analyze Option (c)
Option (c) provides three vectors \((1,2,2),(-1,2,1),(0,8,0)\). Check for linear independence using the determinant of the matrix formed by these vectors. Calculate:\[\begin{vmatrix}1 & -1 & 0 \2 & 2 & 8 \2 & 1 & 0\end{vmatrix}\]Evaluating this determinant, it equals \(-72\). Since the determinant is non-zero, the vectors are linearly independent, forming a basis for \(\mathbf{R}^{3}\).
05
Analyze Option (d)
Option (d) provides three vectors \((1,2,2),(-1,2,1),(0,8,6)\). Again, check for linear independence by calculating the determinant of the matrix formed by these vectors:\[\begin{vmatrix}1 & -1 & 0 \2 & 2 & 8 \2 & 1 & 6\end{vmatrix}\]Evaluating this determinant, it equals \(24\). Since the determinant is non-zero, the vectors are linearly independent, forming a basis for \(\mathbf{R}^{3}\).
06
Conclusion
Options (c) and (d) are bases for \(\mathbf{R}^{3}\) since both contain exactly three vectors which are linearly independent, verified by non-zero determinants.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Basis of Vector Space
In linear algebra, a basis of a vector space is one of the most fundamental concepts. A basis is a set of vectors in a vector space, such as \(\mathbf{R}^3\), which are linearly independent and span the entire space.
To form a basis for \(\mathbf{R}^3\), exactly three vectors are needed. These three vectors must be such that no vector in the set can be written as a linear combination of the others. If you have a basis for \(\mathbf{R}^3\), any vector in \(\mathbf{R}^3\) can be expressed as a linear combination of these basis vectors.
Here's a simple checklist to verify if a set of vectors forms a basis for \(\mathbf{R}^3\):
To form a basis for \(\mathbf{R}^3\), exactly three vectors are needed. These three vectors must be such that no vector in the set can be written as a linear combination of the others. If you have a basis for \(\mathbf{R}^3\), any vector in \(\mathbf{R}^3\) can be expressed as a linear combination of these basis vectors.
Here's a simple checklist to verify if a set of vectors forms a basis for \(\mathbf{R}^3\):
- Ensure there are exactly three vectors in the set.
- Check if the vectors are linearly independent.
- Confirm that the vectors span the space.
Linear Independence
Linear independence is crucial in identifying whether a set of vectors can form a basis. Let's unpack what it means. Vectors are said to be linearly independent if no vector in the set can be represented as a combination of the others.
For instance, consider vectors \((v_1, v_2, v_3)\). To check for linear independence, imagine trying to write one vector as:\[ c_1 \cdot v_1 + c_2 \cdot v_2 + c_3 \cdot v_3 = 0 \]where \(c_1, c_2,\) and \(c_3\) are constants. The vectors are linearly independent if this equation only holds true when \(c_1 = c_2 = c_3 = 0\). In simpler terms, there should be no non-trivial (non-zero) solution for this equation.
If you have three vectors, place them as columns in a matrix and compute the determinant. If the determinant is non-zero, the vectors are linearly independent. This determinant check is a quick and reliable way to confirm linear independence, especially in a three-dimensional space like \(\mathbf{R}^3\).
For instance, consider vectors \((v_1, v_2, v_3)\). To check for linear independence, imagine trying to write one vector as:\[ c_1 \cdot v_1 + c_2 \cdot v_2 + c_3 \cdot v_3 = 0 \]where \(c_1, c_2,\) and \(c_3\) are constants. The vectors are linearly independent if this equation only holds true when \(c_1 = c_2 = c_3 = 0\). In simpler terms, there should be no non-trivial (non-zero) solution for this equation.
If you have three vectors, place them as columns in a matrix and compute the determinant. If the determinant is non-zero, the vectors are linearly independent. This determinant check is a quick and reliable way to confirm linear independence, especially in a three-dimensional space like \(\mathbf{R}^3\).
Determinant Calculation
The determinant is a scalar value that can be computed from a square matrix. It provides essential information about the matrix properties, especially regarding linear transformations and vector independence. When dealing with a set of vectors, determinant calculation is an efficient method to determine their linear independence.
For a set of three vectors in \(\mathbf{R}^3\), you arrange these vectors as columns in a 3x3 matrix. Then, calculate the determinant of this matrix. If the result is not zero, the vectors are linearly independent. Conversely, a zero determinant means they are dependent.
Here's how to compute the determinant for a 3x3 matrix:Given a matrix:\[\begin{vmatrix}a & b & c \d & e & f \g & h & i \\end{vmatrix}\]use the formula:\[ a(ei - fh) - b(di - fg) + c(dh - eg) \] Calculating this value helps us not only verify linear independence but also shows if the set of vectors spans the vector space adequately. Always remember: Non-zero determinant confirms linear independence.
For a set of three vectors in \(\mathbf{R}^3\), you arrange these vectors as columns in a 3x3 matrix. Then, calculate the determinant of this matrix. If the result is not zero, the vectors are linearly independent. Conversely, a zero determinant means they are dependent.
Here's how to compute the determinant for a 3x3 matrix:Given a matrix:\[\begin{vmatrix}a & b & c \d & e & f \g & h & i \\end{vmatrix}\]use the formula:\[ a(ei - fh) - b(di - fg) + c(dh - eg) \] Calculating this value helps us not only verify linear independence but also shows if the set of vectors spans the vector space adequately. Always remember: Non-zero determinant confirms linear independence.