Chapter 2: Problem 39
The cosine space \(\mathbf{F}_{3}\) contains all combinations \(y(x)=A \cos x+B \cos 2 x+\) \(C \cos 3 x\). Find a basis for the subspace that has \(y(0)=0\).
Short Answer
Expert verified
The basis is \( \{\cos x - \cos 3x, \cos 2x - \cos 3x\} \).
Step by step solution
01
Understand the function
We are given a function in the cosine space: \[ y(x) = A \cos x + B \cos 2x + C \cos 3x \]This function can be decomposed into a linear combination of cosine functions with coefficients \(A\), \(B\), and \(C\). We need to find a basis for this function that satisfies the condition \( y(0) = 0 \).
02
Apply the condition y(0)=0
To satisfy the condition \( y(0) = 0 \), substitute \( x = 0 \) into the function:\[ y(0) = A \cos(0) + B \cos(0) + C \cos(0) \]This simplifies to:\[ y(0) = A + B + C \]Since \( y(0) = 0 \), the condition becomes:\[ A + B + C = 0 \]
03
Express one variable in terms of others
From the equation \( A + B + C = 0 \), solve for one of the coefficients in terms of the others, for example, express \( C \):\[ C = -A - B \]
04
Define a basis for the subspace
The general form of the subspace can be written using the parameterized coefficients:\[ y(x) = A (\cos x - \cos 3x) + B (\cos 2x - \cos 3x) \]This expression forms a basis vector for each coefficient, therefore, a basis for the subspace is:\[ \{\cos x - \cos 3x, \cos 2x - \cos 3x\} \]
05
Verify linear independence
To confirm that the basis \( \{\cos x - \cos 3x, \cos 2x - \cos 3x\} \) is linearly independent, consider if any linear combination could result in the zero function. Assume:\[ p(\cos x - \cos 3x) + q(\cos 2x - \cos 3x) = 0 \]This results in:\[ p \cos x + q \cos 2x - (p+q) \cos 3x = 0 \]For this to hold for all \(x\), each coefficient must individually be zero. Thus, \(p = 0\) and \(q = 0\), confirming independence.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Combination
In mathematics, a linear combination refers to an expression constructed from a set of terms by multiplying each term by a constant and adding the results. For the cosine space \( \mathbf{F}_{3}\), our linear combination involves trigonometric functions:
- \( \cos x \)
- \( \cos 2x \)
- \( \cos 3x \)
Basis for Subspace
A basis in a subspace is a set of vectors that are both linearly independent and span the entire subspace. This means that any vector in the subspace can be expressed as a linear combination of the basis vectors. For our function, we are tasked to find a basis that meets the condition \(y(0)=0\).
When we solve the condition, we find that \(A + B + C = 0\). By expressing one variable in terms of others, like \(C = -A - B\), we adjust the terms and redefine our function:\[ y(x) = A (\cos x - \cos 3x) + B (\cos 2x - \cos 3x) \]The above expression implies the basis for the subspace is:
When we solve the condition, we find that \(A + B + C = 0\). By expressing one variable in terms of others, like \(C = -A - B\), we adjust the terms and redefine our function:\[ y(x) = A (\cos x - \cos 3x) + B (\cos 2x - \cos 3x) \]The above expression implies the basis for the subspace is:
- \(\cos x - \cos 3x\)
- \(\cos 2x - \cos 3x\)
Linear Independence
Linear independence is an attribute of a set of vectors wherein no vector in the set is written as a linear combination of others. To verify the linear independence of our basis vectors:
Assume a linear combination results in zero:\[ p(\cos x - \cos 3x) + q(\cos 2x - \cos 3x) = 0 \]Expanding gives:\[ p \cos x + q \cos 2x - (p+q) \cos 3x = 0 \]For the linear independence, each coefficient must individually be zero, leading to the conditions:
Assume a linear combination results in zero:\[ p(\cos x - \cos 3x) + q(\cos 2x - \cos 3x) = 0 \]Expanding gives:\[ p \cos x + q \cos 2x - (p+q) \cos 3x = 0 \]For the linear independence, each coefficient must individually be zero, leading to the conditions:
- \(p \cos x = 0\)
- \(q \cos 2x = 0\)
- \(-(p+q) \cos 3x = 0\)
Coefficients in Trigonometric Functions
In trigonometric functions like the ones in cosine space \(\mathbf{F}_{3}\), coefficients play the crucial role of determining the scaling factor of each trigonometric term within the function. In the function:\[ y(x) = A \cos x + B \cos 2x + C \cos 3x \]The coefficients \(A\), \(B\), and \(C\) can be altered to give different amplitudes to \( \cos x \), \( \cos 2x \), and \( \cos 3x \) respectively.
When solving for the subspace where \(y(0) = 0\), these coefficients are crucial as they define the relationships between the cosine components. The constraint \(A + B + C = 0\) directly ties into how these trigonometric functions relate in the subspace, thus, affecting the entire structure and behavior of the function.
When solving for the subspace where \(y(0) = 0\), these coefficients are crucial as they define the relationships between the cosine components. The constraint \(A + B + C = 0\) directly ties into how these trigonometric functions relate in the subspace, thus, affecting the entire structure and behavior of the function.