/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Assume that \(A\) and \(B\) are ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Assume that \(A\) and \(B\) are \(n \times n\) matrices with det \(A=3\) and det \(B=-2 .\) Find the indicated determinants. \(\operatorname{det}\left(A^{2}\right)\)

Short Answer

Expert verified
The determinant is 9.

Step by step solution

01

Understanding Matrix Powers and Determinants

The determinant of a matrix raised to a power can be found by raising the determinant of the matrix to that same power. If you have a determinant of a matrix given as \( \text{det}(A) \), then \( \text{det}(A^k) = (\text{det}(A))^k \) for any integer \( k \).
02

Apply the Property to Given Data

We need \( \text{det}(A^2) \). Since \( \text{det}(A) = 3 \), we apply the property from the previous step: \( \text{det}(A^2) = (\text{det}(A))^2 = 3^2 \).
03

Calculate the Determinant

Now, calculate \( 3^2 \). This gives us \( 9 \). Therefore, \( \text{det}(A^2) = 9 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Powers
Matrix powers involve raising a matrix to a certain exponent, such as squaring it. When you raise a matrix to a power, it's similar to multiplying the matrix by itself multiple times. For instance, if you square matrix \( A \), which is expressed as \( A^2 \), it means multiplying \( A \) by itself, i.e., \( A \times A \). This process is only defined for square matrices (matrices with the same number of rows and columns).
Understanding how matrix powers work is crucial, particularly when dealing with determinants. Remember, the power of a matrix affects its determinant in a very predictable way. In the case where you already know \( \text{det}(A) \), you can easily find \( \text{det}(A^k) \) by computing \( (\text{det}(A))^k \).
The concept of matrix powers is not merely about multiplying matrices but also understanding how these operations affect various matrix properties, such as invertibility and linear transformation characteristics. This provides a deeper insight into linear algebra where matrix manipulation plays a key role.
Determinant Properties
Determinants are a special number assigned to a square matrix, depicting certain properties of the matrix, such as its invertibility. A non-zero determinant indicates the matrix is invertible, whereas a zero determinant means it's singular (not invertible).
Several properties of determinants make them incredibly useful in linear algebra. For instance, if you multiply a matrix by a scalar, the determinant of the resulting matrix is the scalar multiplied by the original determinant. If \( A \) is multiplied by a scalar \( c \), then \( \text{det}(cA) = c^n \times \text{det}(A) \) where \( n \) is the size of the matrix.
Another important property pertains to matrix powers: \( \text{det}(A^k) = (\text{det}(A))^k \). This property allows a quick calculation of the determinant for powers of a matrix, as seen in the original exercise with \( A^2 \). Understanding and applying these properties are keys to efficiently solving determinant-related problems.
Matrix Multiplication
Matrix multiplication involves multiplying the entries of one matrix with the corresponding entries of another matrix based on specific rules. It is not as straightforward as multiplying numbers. In fact, multiplying two matrices is only possible if their dimensions align: the number of columns in the first matrix must be equal to the number of rows in the second matrix.
Matrix multiplication is associative and distributive but not commutative. This means if you have matrices \( A \) and \( B \), then \( A \cdot B eq B \cdot A \) in general. Therefore, the order in which you multiply matrices matters.
Understanding matrix multiplication is vital as it is used extensively in various fields such as computer graphics, structural analysis, and physics. It also underpins many advanced operations and properties in linear algebra, including transformations and solving systems of linear equations. Mastering this concept allows you to appreciate the full power of matrices and their utility in problem-solving.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the Perron root and the corresponding Perron eigenvector of \(A\) $$A=\left[\begin{array}{lll} 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{array}\right]$$

Prove that if \(A\) is a diagonalizable matrix such that every eigenvalue of \(A\) is either 0 or 1 , then \(A\) is idempotent (that is, \(A^{2}=A\) ).

It can be shown that a nonnegative \(n \times n\) matrix is irreducible if and only if \((I+A)^{n-1}>0 .\) Use this criterion to determine whether the matrix \(A\) is irreducible. If \(A\) is reducible, find a permutation of its rows and columns that puts \(A\) into the block form \\[ \left[\begin{array}{ll} B & C \\ O & D \end{array}\right] \\] $$A=\left[\begin{array}{llll} 0 & 0 & 1 & 0 \\ 0 & 0 & 1 & 1 \\ 1 & 0 & 0 & 0 \\ 1 & 1 & 0 & 0 \end{array}\right]$$

A scientist places two strains of bacteria, \(X\) and \(Y\), in petri dish. Initially, there are 400 of \(X\) and 500 of \(Y\) The two bacteria compete for food and space but do not feed on each other. If \(x=x(t)\) and \(y=y(t)\) are the numbers of the strains at time \(t\) days, the growth rates of the two populations are given by the system \\[ \begin{array}{l} x^{\prime}=1.2 x-0.2 y \\ y^{\prime}=-0.2 x+1.5 y \end{array} \\] (a) Determine what happens to these two populations by solving the system of differential equations. (b) Explore the effect of changing the initial populations by letting \(x(0)=a\) and \(y(0)=b .\) Describe what happens to the populations in terms of \(a\) and \(b\)

If \(A\) is an invertible \(n \times n\) matrix, show that adj \(A\) is also invertible and that \\[ (\operatorname{adj} A)^{-1}=\frac{1}{\operatorname{det} A} A=\operatorname{adj}\left(A^{-1}\right) \\]

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.