Chapter 4: Problem 47
Prove that if \(A\) is a diagonalizable matrix such that every eigenvalue of \(A\) is either 0 or 1 , then \(A\) is idempotent (that is, \(A^{2}=A\) ).
Short Answer
Expert verified
If all eigenvalues of a diagonalizable matrix are 0 or 1, the matrix is idempotent \((A^2 = A)\).
Step by step solution
01
Understanding Diagonalization
If a matrix \(A\) is diagonalizable, it means there exists an invertible matrix \(P\) and a diagonal matrix \(D\) such that \(A = PDP^{-1}\). Here, \(D\) will have the eigenvalues of \(A\) on its diagonal.
02
Analyzing the Eigenvalues
Given that every eigenvalue of \(A\) is either 0 or 1, the diagonal matrix \(D\) can be represented as \(D = \text{diag}( ext{eigenvalue}(1), ext{eigenvalue}(2), ext{...}))\) where each eigenvalue is 0 or 1.
03
Calculating \(D^2\)
Since \(D\) is a diagonal matrix, \(D^2\) will also be a diagonal matrix where each diagonal element is the square of the corresponding diagonal element in \(D\). So, \(D^2 = \text{diag}(\text{eigenvalue}(1)^2, \text{eigenvalue}(2)^2, \dots)\).
04
Understanding Each Eigenvalue Square
Consider each eigenvalue squared: \(0^2 = 0\) and \(1^2 = 1\). Therefore, \(D^2 = D\) since squaring the eigenvalues doesn't change the diagonal elements.
05
Relating \(A^2\) to \(D^2\)
Use the diagonalization relation: \(A^2 = (PDP^{-1})(PDP^{-1}) = PD^2P^{-1}\). We know \(D^2 = D\), so \(A^2 = PDP^{-1} = A\).
06
Conclusion
Thus, we have shown that \(A^2 = A\). Therefore, the matrix \(A\) is idempotent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Diagonalizable Matrix
A matrix is termed diagonalizable if it can be expressed in a specific form involving another matrix that is diagonal. Simply put, a matrix \(A\) is diagonalizable if there exists an invertible matrix \(P\) such that:
- \(A = PDP^{-1}\)
- \(D\) is a diagonal matrix
Eigenvalues
Eigenvalues are special numbers associated with a matrix that help determine its fundamental characteristics. If you evaluate the matrix \(A\) for its eigenvectors \(v\), then \(\lambda\) is an eigenvalue satisfying:
- \(Av = \lambda v\)
Idempotent Matrix
An idempotent matrix is a special type of matrix where applying it twice (or more times) does not change the result beyond the first application. In more mathematical terms, a matrix \(A\) is idempotent if:
- \(A^2 = A\)
Diagonal Matrix
A diagonal matrix is one where all off-diagonal entries are zero; only the diagonal elements may be non-zero. If represented as \(D\), these matrices take the following form:
- \(D = \text{diag}(d_1, d_2, \dots, d_n)\)