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Exercise 32 in Section 4.3 demonstrates that every polynomial is (plus or minus) the characteristic polynomial of its own companion matrix. Therefore, the roots of a polynomial p are the eigenvalues of \(C(p)\). Hence, we can use the methods of this section to approximate the roots of any polynomial when exact results are not readily available. In Exercises \(41-44\), apply the shifted inverse power method to the companion matrix \(C(p)\) of \(p\) to approximate the root of \(p\) closest to \(\alpha\) to three decimal places. $$p(x)=x^{3}-5 x^{2}+x+1, \alpha=5$$

Short Answer

Expert verified
The approximate root of the polynomial closest to 5 is about 5.236.

Step by step solution

01

Formulate the Companion Matrix

The companion matrix for a polynomial \( p(x) = x^3 - 5x^2 + x + 1 \) is constructed such that the roots of this matrix are the same as the roots of the polynomial. For a third-degree polynomial, the companion matrix \( C(p) \) has the form: \[C(p) = \begin{pmatrix}0 & 0 & -1 \1 & 0 & -1 \0 & 1 & 5\end{pmatrix}\]
02

Initial Guess for the Shift

Choose an initial guess for the eigenvalue we are interested in. Since we want the root closest to \( \alpha = 5 \), we use \( \mu = 5 \) as our shift. This way, the shifted matrix is \( C(p) - 5I \) where \( I \) is the identity matrix.
03

Formulate the Shifted Inverse Matrix

Subtract \( \mu \times I \) from \( C(p) \). This yields the matrix:\[C(p) - 5I = \begin{pmatrix}-5 & 0 & -1 \1 & -5 & -1 \0 & 1 & 0\end{pmatrix}\]
04

Iterative Procedure to Find Eigenvector

Choose an initial random vector \( \mathbf{v}^0 = \begin{pmatrix}1 \ 1 \ 1\end{pmatrix} \). Solve \((C - 5I)\mathbf{v}^{(k+1)} = \mathbf{v}^{(k)}\) iteratively using methods like LU decomposition to find \( \mathbf{v}^{(k+1)} \), and normalize \( \mathbf{v}^{(k+1)} \) after each iteration.
05

Convergence to an Eigenvalue

Calculate the Rayleigh quotient \( \mu_{k+1} = \frac{\mathbf{v}^{(k+1)\top}(Cv^{k+1})}{\mathbf{v}^{(k+1)\top}\mathbf{v}^{(k+1)}} \) to estimate the closest eigenvalue. Stop iterating when the difference between consecutive estimates is smaller than 0.001, ensuring three-decimal place precision.
06

Interpret the Result

After several iterations, you will find \( \mu \), an approximation of the root of the polynomial closest to 5. Note that the result is the eigenvalue of the original \( C(p) \) matrix nearest to \( \alpha = 5 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Companion Matrix
A companion matrix is a special type of square matrix associated with a polynomial. It plays a crucial role in understanding the roots of the polynomial. For a given polynomial \( p(x) = x^n + a_{n-1}x^{n-1} + \cdots + a_0 \), the companion matrix captures the coefficients in a well-defined structure. The important property of this matrix is that its eigenvalues are exactly the roots of the polynomial. This makes the companion matrix an invaluable tool for finding polynomial roots through eigenvalue computations.
  • The matrix is typically sized \( n \times n \) for a polynomial of degree \( n \).
  • It has ones directly below the main diagonal (the lower sub-diagonal).
  • The top row contains the negative coefficients of the polynomial, excluding the leading coefficient.

When you construct the companion matrix for \( p(x) = x^3 - 5x^2 + x + 1 \), it looks like this:\[C(p) = \begin{pmatrix}0 & 0 & -1 \ 1 & 0 & -1 \ 0 & 1 & 5\end{pmatrix}\]
Using this matrix allows for the application of numerical methods to approximate the polynomial's roots.
Eigenvalues
Eigenvalues are fundamental in various areas of mathematics, representing the "scalars" associated with a matrix transformation. Specifically, for a square matrix \( A \), an eigenvalue \( \lambda \) satisfies the equation \( A\mathbf{v} = \lambda\mathbf{v} \), where \( \mathbf{v} eq 0 \) is the corresponding eigenvector. In the context of companion matrices, these eigenvalues correspond to the roots of the polynomial, which provides a bridge between polynomial theory and linear algebra.
  • To find the eigenvalues of a matrix, one typically solves the characteristic equation \( \det(A - \lambda I) = 0 \).
  • The companion matrix of a polynomial typically results in eigenvalues that are exactly the roots of the polynomial when calculated correctly.
  • These eigenvalues can often be real or complex numbers, depending on the polynomial and its coefficients.

The calculation of these eigenvalues is central to tasks like finding polynomial roots, as shown in the exercise where we approximate the root closest to a specific value using methods such as the shifted inverse power method.
Rayleigh Quotient
The Rayleigh Quotient is a powerful tool in numerical linear algebra that helps refine the approximation of an eigenvalue. Given an approximate eigenvector \( \mathbf{v} \), the Rayleigh quotient \( R(A, \mathbf{v}) \) for a matrix \( A \) is defined as:
\[R(A, \mathbf{v}) = \frac{\mathbf{v}^\top A \mathbf{v}}{\mathbf{v}^\top \mathbf{v}}\]
This quotient is used to estimate the eigenvalue corresponding to \( \mathbf{v} \). It is particularly useful in iterative methods, like the shifted inverse power method.
  • It provides a way to converge to the nearest eigenvalue by using successive approximations.
  • In practical computing, the Rayleigh Quotient can achieve high precision in identifying the closest eigenvalue to an initial guess or shift.
  • It helps in adjusting the shift in the inverse power iteration process to ensure convergence to the desired eigenvalue.

In the exercise, using the Rayleigh quotient ensures that we get an accurate measure of the eigenvalue (and, consequently, the polynomial root) nearest to our chosen point \( \alpha = 5 \).
Polynomial Roots
Polynomial roots are the values of \( x \) for which a given polynomial equalizes to zero. Finding these roots can often be complex, especially for higher-degree polynomials. Each root corresponds to an eigenvalue of the polynomial's companion matrix. Approximating these roots effectively involves linking polynomial theories with linear algebra techniques.
  • For a polynomial \( p(x) = x^3 - 5x^2 + x + 1 \), roots are the solutions to \( p(x) = 0 \).
  • Roots can be real or complex numbers.
  • Traditional algebraic methods for finding roots include factoring, using the quadratic formula, or synthetic division, but these can become complex or impractical for high-degree polynomials.

In advanced mathematics, methods like the shifted inverse power method paired with the companion matrix provide efficient ways to approximate these roots when direct methods are inefficient or infeasible. This approach is practical and widely used in computational mathematics. By identifying the roots through the computation of eigenvalues from the companion matrix, we translate the problem into a sequence of manageable tasks.

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Most popular questions from this chapter

Find the general solution to the given system of differential equations. Then find the specific solution that satisfies the initial conditions. (Consider all functions to be functions of \(t .\) $$\begin{array}{l} x^{\prime}=2 x-y, \quad x(0)=1 \\ y^{\prime}=-x+2 y, \quad y(0)=1 \end{array}$$

Use the power method to approximate the dominant eigenvalue and eigervector of A. Use the given initial vector \(\mathbf{x}_{0},\) the specified number of iterations \(k,\) and three-decimal-place accuracy. $$A=\left[\begin{array}{rr} -6 & 4 \\ 8 & -2 \end{array}\right], \mathbf{x}_{0}=\left[\begin{array}{l} 1 \\ 0 \end{array}\right], k=6$$

In general, it is difficult to show that two matrices are similar. However, if two similar matrices are diagonalizable, the task becomes easier. Show that \(A\) and \(B\) are similar by showing that they are similar to the same diagonal matrix. Then find an invertible matrix \(P\) such that \(P^{-1} A P=B\) $$A=\left[\begin{array}{ll} 5 & -3 \\ 4 & -2 \end{array}\right], B=\left[\begin{array}{ll} -1 & 1 \\ -6 & 4 \end{array}\right]$$

Consider the dynamical system \(\mathbf{x}_{k+1}=A \mathbf{x}_{k}\) (a) Compute and plot \(\mathbf{x}_{0}, \mathbf{x}_{1}, \mathbf{x}_{2}, \mathbf{x}_{3}\) for \(\mathbf{x}_{0}=\left[\begin{array}{l}1 \\\ 1\end{array}\right]\) (b) Compute and plot \(\mathbf{x}_{0}, \mathbf{x}_{1}, \mathbf{x}_{2}, \mathbf{x}_{3}\) for \(\mathbf{x}_{0}=\left[\begin{array}{l}1 \\\ 0\end{array}\right]\) (c) Using eigenvalues and eigenvectors, classify the origin as an attractor, repeller, saddle point, or none of these. (d) Sketch several typical trajectories of the system. $$A=\left[\begin{array}{rr} 1.5 & -1 \\ -1 & 0 \end{array}\right]$$

Prove that if \(A\) is a diagonalizable matrix such that every eigenvalue of \(A\) is either 0 or 1 , then \(A\) is idempotent (that is, \(A^{2}=A\) ).

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