Chapter 64: Problem 2
\(\ln \frac{1+x}{1-x}=2\left(x+\frac{x^{3}}{3}+\frac{x^{5}}{5}+\cdots\right)\) fü \(|x|<1\) (s. A 62.2)
Short Answer
Expert verified
The series is the valid expansion for \( \ln \frac{1+x}{1-x} \) for \(|x|<1\).
Step by step solution
01
Express Natural Logarithm Using Integral
The natural logarithm can be expressed as an integral: \( \ln \left( \frac{1+x}{1-x} \right) = \int_0^x \frac{d}{dt} \ln \left( \frac{1+t}{1-t} \right) \, dt = \int_0^x \frac{1}{1+t} + \frac{1}{1-t} \, dt \). Simplify to: \( \int_0^x \left( \frac{2}{1-t^2} \right) \, dt \).
02
Use Partial Fraction Decomposition
Partial fraction decomposition of \( \frac{2}{1-t^2} \) gives \( \frac{1}{1-t} + \frac{1}{1+t} \). Therefore, \( \ln \left( \frac{1+x}{1-x} \right) = \int_0^x \frac{2}{1-t^2} \, dt = \ln \left( \frac{1+t}{1-t} \right) \bigg|_0^x = 2 \left( \text{atanh}(x) \right) \).
03
Maclaurin Series Expansion for atanh(x)
The Maclaurin series expansion for \( \text{atanh}(x) \) is \( x + \frac{x^3}{3} + \frac{x^5}{5} + \cdots \). Multiply this series by 2 to get the series on the right side of the equation: \( 2 \left( x + \frac{x^3}{3} + \frac{x^5}{5} + \cdots \right) \).
04
Compare both sides of the equation
Both sides of the equation represent the expansion for \( \ln \left( \frac{1+x}{1-x} \right) \) in terms of \( x \). Hence, we've shown that the given infinite series accurately represents the natural logarithm expression as long as \( |x| < 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a fundamental concept in calculus and mathematics in general. It is often associated with the constant \( e \), which is approximately 2.71828. When we take the natural logarithm of a number, we are essentially asking "what power must \( e \) be raised to, to obtain this number?"
Natural logarithms are used extensively in various mathematical expressions and are vital in solving equations involving exponential growth or decay. For example, \( \ln(1+x) \) can be expressed as an integral:
Natural logarithms are used extensively in various mathematical expressions and are vital in solving equations involving exponential growth or decay. For example, \( \ln(1+x) \) can be expressed as an integral:
- \( \ln(1+x) = \int_0^x \frac{1}{1+t} \, dt \)
Partial Fraction Decomposition
Partial fraction decomposition is a technique that helps simplify complex rational expressions. It's particularly useful when you need to integrate functions that contain polynomial ratios. The goal here is to express a complicated fraction as a sum of simpler fractions.
For example, consider the expression \( \frac{2}{1-t^2} \), which can be decomposed using:
In our problem, using partial fraction decomposition simplifies the integral of \( \frac{2}{1-t^2} \) to a form suitable for direct integration, which is key to transforming the integral into a recognizable function or series.
For example, consider the expression \( \frac{2}{1-t^2} \), which can be decomposed using:
- \( \frac{2}{1-t^2} = \frac{1}{1-t} + \frac{1}{1+t} \)
In our problem, using partial fraction decomposition simplifies the integral of \( \frac{2}{1-t^2} \) to a form suitable for direct integration, which is key to transforming the integral into a recognizable function or series.
Series Expansion
Series expansion is a powerful tool in mathematics used to approximate complex functions through a sum of simpler terms. A common type of series is the Maclaurin series, which is a Taylor series expansion about zero.
The Maclaurin series for a function \( f(x) \) can be expressed as:
This concept is fundamental for mathematicians and engineers who often deal with functions that are too complex to work with directly but are manageable when expressed as a series.
The Maclaurin series for a function \( f(x) \) can be expressed as:
- \( f(x) = f(0) + f'(0)x + \frac{f''(0)x^2}{2!} + \frac{f'''(0)x^3}{3!} + \cdots \)
- \( \text{atanh}(x) = x + \frac{x^3}{3} + \frac{x^5}{5} + \cdots \)
This concept is fundamental for mathematicians and engineers who often deal with functions that are too complex to work with directly but are manageable when expressed as a series.
Inverse Hyperbolic Functions
Inverse hyperbolic functions, like \( \text{atanh}(x) \), are analogous to inverse trigonometric functions but appear in hyperbolic contexts. They are important in different areas of mathematics, including calculus and complex analysis.
The function \( \text{atanh}(x) \), or inverse hyperbolic tangent, is defined as:
because they frequently show up in practical applications, such as in physics, engineering, and even in statistical models.
These functions help simplify complex expressions and provide a link between algebraic formulas and their geometrical or physical interpretations.
The function \( \text{atanh}(x) \), or inverse hyperbolic tangent, is defined as:
- \( \text{atanh}(x) = \frac{1}{2} \ln \left( \frac{1+x}{1-x} \right) \)
because they frequently show up in practical applications, such as in physics, engineering, and even in statistical models.
These functions help simplify complex expressions and provide a link between algebraic formulas and their geometrical or physical interpretations.