Chapter 63: Problem 4
. Zeige mittels Reihenmultiplikation, \(\mathrm{daB} \mathrm{e}^{x} \mathrm{e}^{y}=\mathrm{e}^{x+y}\) ist (Additionstheorem der Exponentialfunktion)
Short Answer
Expert verified
The exercise shows that \(e^x e^y = e^{x+y}\) by using power series multiplication.
Step by step solution
01
Express Each Exponential Function as a Series
Begin by expressing the exponential functions as power series. For a real number \(x\), the power series expansion of \(e^x\) is given by:\[ e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} \]Similarly, express \(e^y\) as:\[ e^y = \sum_{m=0}^{\infty} \frac{y^m}{m!} \]
02
Multiply the Two Power Series
To multiply the two series, we need to find the product:\( (e^x)(e^y) = \left( \sum_{n=0}^{\infty} \frac{x^n}{n!} \right) \left( \sum_{m=0}^{\infty} \frac{y^m}{m!} \right) \).This requires the use of Cauchy product for series, which states that the product of two series can be expressed as:\[ \sum_{k=0}^{\infty} \left( \sum_{j=0}^{k} \frac{x^j}{j!} \frac{y^{k-j}}{(k-j)!} \right) \].
03
Simplify the Expression
The expression from Step 2 can be rewritten by recognizing the term within the sum:\[ \sum_{k=0}^{\infty} \frac{1}{k!} \sum_{j=0}^{k} \binom{k}{j} x^j y^{k-j} \].Using the binomial theorem, \( (x+y)^k = \sum_{j=0}^{k} \binom{k}{j} x^j y^{k-j} \), the sum simplifies to: \[ \sum_{k=0}^{\infty} \frac{(x+y)^k}{k!} \], which is the series expansion of \(e^{x+y}\).
04
Conclude the Proof
The simplified power series \( \sum_{k=0}^{\infty} \frac{(x+y)^k}{k!} \) matches the series expansion of \(e^{x+y}\). This shows that:\[ e^x e^y = e^{x+y} \].This validates the addition theorem of the exponential function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Series
A power series is a way to represent functions as an infinite sum of terms calculated from the values of their variable's powers. In simple terms, it's like building a function using lots of little building blocks. This concept is pivotal in calculus and analysis as it helps to approximate complex functions with simpler polynomial-like expressions. When working with exponential functions like \( e^x \), the power series becomes particularly useful.
For the exponential function \( e^x \), the power series is given by:
For the exponential function \( e^x \), the power series is given by:
- \( e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} \)
Series Multiplication
Series multiplication involves multiplying two infinite series together, which can be a bit complex. However, using certain rules like the Cauchy product formula, it becomes manageable.
To multiply two power series, such as for \( e^x \) and \( e^y \), we follow this structure:
To multiply two power series, such as for \( e^x \) and \( e^y \), we follow this structure:
- \( (e^x)(e^y) = \left( \sum_{n=0}^{\infty} \frac{x^n}{n!} \right) \left( \sum_{m=0}^{\infty} \frac{y^m}{m!} \right) \)
Cauchy Product
The Cauchy product is a clever method to find the product of two power series. Named after the mathematician Augustin-Louis Cauchy, it provides a way to systematically combine series. It states that the product of two series, \( \sum_{n=0}^{\infty} a_n \) and \( \sum_{m=0}^{\infty} b_m \), results in a new series:
- \( \sum_{k=0}^{\infty} \left( \sum_{j=0}^{k} a_j b_{k-j} \right) \)
- \( \sum_{k=0}^{\infty} \left( \sum_{j=0}^{k} \frac{x^j}{j!} \frac{y^{k-j}}{(k-j)!} \right) \)
Binomial Theorem
The Binomial Theorem is a key mathematical idea with far-reaching applications. It helps expand expressions that are raised to a power, particularly useful for binomials, which are expressions with two terms.
For a power \( n \), the theorem states:
When we equate these expansions with series forms, it simplifies our understanding of series like \( \sum_{k=0}^{\infty} \frac{(x+y)^k}{k!} \), leading to solving and proving fundamental equations like \( e^{x+y} \). The Binomial Theorem not only clarifies polynomial expansion but also strengthens the bridge between algebra and calculus.
For a power \( n \), the theorem states:
- \( (x+y)^n = \sum_{j=0}^{n} \binom{n}{j} x^j y^{n-j} \)
When we equate these expansions with series forms, it simplifies our understanding of series like \( \sum_{k=0}^{\infty} \frac{(x+y)^k}{k!} \), leading to solving and proving fundamental equations like \( e^{x+y} \). The Binomial Theorem not only clarifies polynomial expansion but also strengthens the bridge between algebra and calculus.