Chapter 18: Problem 4
Die Funktion \(x \mapsto 1 / x\) ist auf jedem Intervall \([a, b]\) dehnungsbeschränkt, das 0 nicht cnthält
Short Answer
Expert verified
The function \(x \mapsto 1/x\) is Lipschitz continuous on any interval \([a,b]\) that does not include zero.
Step by step solution
01
Understand the Function
The problem gives us the function \( x \mapsto \frac{1}{x} \) and states that we need to examine its properties on any interval \([a, b]\) that does not include zero.
02
Define Dehnungsbeschränkt (Lipschitz Condition)
A function is Lipschitz continuous (dehnungsbeschränkt) on an interval if there exists a constant \(L\) such that for all \(x, y\) in the interval, \(|f(x) - f(y)| \leq L|x - y|\). This means the function does not have any abrupt changes in the interval.
03
Check the Derivative for Boundedness
Consider the derivative of \(f(x) = \frac{1}{x}\), which is \(f'(x) = -\frac{1}{x^2}\). Since \([a,b]\) does not include zero, this derivative is continuous and does not go to infinity or become undefined. Thus, \(f'(x)\) is bounded on \([a, b]\).
04
Apply Mean Value Theorem
By the Mean Value Theorem, since \(f\) is continuous on \([a,b]\) and differentiable on \((a,b)\), there exists a point \(c \in (a, b)\) such that \( \frac{f(b) - f(a)}{b-a} = f'(c)\), which implies \(|f(b) - f(a)| \leq K\cdot |b-a|\), where \(K = \max_{x \in [a,b]} |f'(x)|\).
05
Conclude Lipschitz Condition
Because the derivative \(f'(x)\) is bounded on the interval \([a,b]\) as it does not involve zero, the function \(f(x) = \frac{1}{x}\) satisfies the Lipschitz condition, meaning it is dehnungsbeschränkt on the interval.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
A derivative represents the rate at which a function changes as its input changes. For any point on a curve, the derivative gives the slope of the tangent at that point. In the context of the function \( f(x) = \frac{1}{x} \), the derivative is \( f'(x) = -\frac{1}{x^2} \). This derivative tells us how the function changes as we move along the \( x \)-axis. Since \( f(x) \) is defined on an interval \([a, b]\) not containing zero, the derivative is well-behaved, meaning it is finite and continuous in this range.
- A finite derivative implies the function isn't experiencing infinite rates of change.
- A continuous derivative means the function doesn't have sudden jumps in its behavior.
Mean Value Theorem
The Mean Value Theorem (MVT) is a fundamental idea in calculus that connects the behaviors of a function over an interval to the behavior at a specific point. Simply put, if a function is continuous on \([a, b]\) and differentiable on \((a, b)\), then there is at least one point \( c \) in \((a, b)\) where the instantaneous rate of change (the derivative) is equal to the average rate of change over the interval. In mathematical terms, MVT states:\[ f'(c) = \frac{f(b) - f(a)}{b - a} \]Here, applying MVT to the function \( f(x) = \frac{1}{x} \) confirms that between any two points \( a \) and \( b \), the function behaves predictably.
- The theorem ensures that the function's slope at some point equals the average slope across the interval.
- This helps us ascertain that the function does not exhibit wild oscillations on the interval.
Lipschitz Condition
Lipschitz continuity, or dehnungsbeschränkt, is a condition ensuring a function has controlled behavior within a certain range. For a function to be Lipschitz continuous on an interval \([a, b]\), there must exist a constant \( L \) such that for every pair of points \( x \) and \( y \) within that interval, the difference in function values \(|f(x) - f(y)|\) is at most \( L \times |x - y|\).For the function \( f(x) = \frac{1}{x} \), finding such a constant \( L \) means verifying that the slope of the function is bounded. This assurance comes by examining the derivative \( f'(x) = -\frac{1}{x^2} \). If this derivative is bounded for \( x \) in \([a, b]\), the function adheres to the Lipschitz condition:
- The existence of a constant \( K = \max_{x \in [a,b]} |f'(x)| \) provides a cap on how steep the function gets.
- The function changes at a rate that can be predictably controlled, preventing abrupt spikes or dips.
Continuous Function
A continuous function is one that doesn't exhibit jumps, breaks, or holes across the domain. This notion is central to understanding the behavior of functions like \( f(x) = \frac{1}{x} \) on intervals excluding zero. For our function to be continuous on an interval \([a, b]\), it needs to smoothly transition from point to point without abrupt changes.
- Mathematically, if \( x_1 \to x_2 \), then the function's value \( f(x_1) \to f(x_2) \).
- When considering \( f(x) = \frac{1}{x} \), it's pivotal that \([a, b]\) doesn't cross zero – ensuring \( f(x) \) remains defined and continuous.