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The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of five minutes and a standard deviation of two minutes.

Seventy percent of the time, it takes more than how many minutes to find a parking space?

a. 1.24

b. 2.41

c. 3.95

d. 6.05

Short Answer

Expert verified

The answer is option c

That is seventy percent of the time, it takes more than 3.95minutes to find a parking space.

Step by step solution

01

Given information

Given in the question that

Mean=5

Standard deviation =2

k=required time

02

Solution

The calculation is show below,

P(x>k)=0.70

Px−μσ>k−μσ=0.70

PZ>k−52=0.70

PZ<k−52=1−0.70

PZ<k−52=0.30

k−52=−0.5244

From the standard normal table the value of z will be (−0.5244)

k−5=−0.5244×2

k=−1.0488+5

=3.9512

≈3.95

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