/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.6.72 The length of time it takes to f... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 6: Q.6.72 (page 390)

The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of five minutes and a standard deviation of two minutes.

Seventy percent of the time, it takes more than how many minutes to find a parking space?

a. 1.24

b. 2.41

c. 3.95

d. 6.05

Short Answer

Expert verified

The answer is option c

That is seventy percent of the time, it takes more than 3.95minutes to find a parking space.

Step by step solution

01

Given information

Given in the question that

Mean=5

Standard deviation =2

k=required time

02

Solution

The calculation is show below,

P(x>k)=0.70

Px鈭�渭蟽>k鈭�渭蟽=0.70

PZ>k鈭�52=0.70

PZ<k鈭�52=1鈭�0.70

PZ<k鈭�52=0.30

k鈭�52=鈭�0.5244

From the standard normal table the value of z will be (鈭�0.5244)

k鈭�5=鈭�0.5244脳2

k=鈭�1.0488+5

=3.9512

鈮�3.95

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Is X~N(0,1) a standardized normal distribution? Why or why not?

In a normal distribution, x = 6 and z = 鈥�1.7. This tells you that x = 6 is ____ standard deviations to the ____ (right or left) of the mean.

In the 1992 presidential election, Alaska鈥檚 40 election districts averaged 1,956.8 votes per district for President Clinton.

The standard deviation was 572.3. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district.

a. State the approximate distribution of X.

b. Is 1,956.8 a population mean or a sample mean? How do you know?

c. Find the probability that a randomly selected district had fewer than 1,600 votes for President Clinton. Sketch the graph and write the probability statement.

d. Find the probability that a randomly selected district had between 1,800 and 2,000 votes for President Clinton.

e. Find the third quartile for votes for President Clinton.

What is the area to the right of three?

According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66inches and a standard deviation of 2.5inches. Suppose one Asian adult male is randomly chosen. Let X = height of the individual.

a.X~_____(_____,_____)

b. Find the probability that the person is between 65and 69inches. Include a sketch of the graph, and write a probability statement.

c. Would you expect to meet many Asian adult males over 72 inches? Explain why or why not, and justify your answer numerically.
See all solutions

Recommended explanations on Math Textbooks

Statistics

Read Explanation

Pure Maths

Read Explanation

Applied Mathematics

Read Explanation

Geometry

Read Explanation

Logic and Functions

Read Explanation

Theoretical and Mathematical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.