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Using the information from Example 6.12, answer the following:

  1. The middle 40%of mandarin oranges from this farm is between __ and __.
  2. Find the 16thpercentile and interpret it in a complete sentence

Short Answer

Expert verified
  1. The middle 40%of mandarin oranges from this farm are between 5.72424and5.97576in diameter.
  2. The table value of the 16th percentile islocalid="1649343002299" 5.61

Step by step solution

01

Given Information (Part-a)

Given in the question that, X follows Normal distribution with,

μ=5.85

σ=0.24

02

Solution of the Problem (Part-a)

For the middle40%data,

Let a and b be the limits

P[a<X<b]=0.40

1−P[a<X<b]=1−0.40=0.60

Due to symmetry,

P[X<a]=0.30andP[X>b]=0.30

For standard normal variable z, using z table we can say that.,

P[Z<−0.524]=0.30and P[Z>0.524]=0.30

Using zthe score formula,

localid="1648298928299" a=μ+(zσ)=5.85+(−0.524×0.24)=5.72424

localid="1648298940022" b=μ+(zσ)=5.85+(0.524×0.24)=5.97576

03

Given Information (Part-b)

Given in the question that,Xfollows Normal distribution with,

μ=5.85

σ=0.24

04

Solution of the Problem (Part-b)

Compute the 16thpercentile as follow:

P(x<k)=0.16

Px−μσ<k−μσ=0.16

PZ<k−5.850.24=0.16

k−5.850.24=−0.9945From standardnormal table

k−5.85=−0.9945×0.24

k=−0.23868+5.85

k≈5.61

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