/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.6.70 The length of time it takes to f... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 6: Q.6.70 (page 390)

The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of five minutes and a standard deviation of two minutes.

Based upon the given information and numerically justified, would you be surprised if it took less than one minute to find a parking space?

a. Yes

b. No

c. Unable to determine

Short Answer

Expert verified

The correct answer is an option a because if anyone finds the parking space before the expected time every one will be surprised

Step by step solution

01

Given information

Given in the question that

Mean=5

Standard deviation=2

02

Solution

From the given data in the question mean is 5and the standard deviation is 2

If anyone finds the parking space less than the one minute it will be a shock to everyone because the minimum time that is required to find the parking space is calculated below,

5-2

=3

So it is impossible to find a parking space less than 3minutes

If anyone is find the parking space less than the expected time. It will be a surprise to everyone.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A bottle of water contains 12.05fluid ounces with a standard deviation of 0.01ounces. Define the random variable Xin words. X=____________.

In the 1992 presidential election, Alaska's 40 election districts averaged 1,956.8 votes per district for President Clinton. The standard deviation was 572.3. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X=the number of votes for President Clinton for an election district be known.

a. State the approximate distribution of X

b. Is 1,956.8a population mean or a sample mean? How do you know?

c. Find the probability that a randomly selected district had fewer than 1,600votes for President Clinton. Sketch the graph and write the probability statement.

d. Find the probability that a randomly selected district had between 1,800and 2,000votes for President Clinton.

e. Find the third quartile for votes for President Clinton.

Suppose that Ricardo and Anita attend different colleges. Ricardo's GPA is the same as the average GPA at his school. Anita's GPA is 0.70 standard deviations above her school average. In complete sentences, explain why each of the following statements may be false.

a. Ricardo's actual GPA is lower than Anita's actual GPA.

b. Ricardo is not passing because his z-score is zero.

c. Anita is in the 70th percentile of students at her college.

齿词狈(鈥�4,1)

What is the median?

Suppose a normal distribution has a mean of six and a standard deviation of 1.5. What is the z-score of x = 5.5?
See all solutions

Recommended explanations on Math Textbooks

Geometry

Read Explanation

Discrete Mathematics

Read Explanation

Theoretical and Mathematical Physics

Read Explanation

Calculus

Read Explanation

Probability and Statistics

Read Explanation

Mechanics Maths

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.