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A teacher predict that the distribution of grades on the final exam will be and they are recorded in table 11.27

The actual distribution for a class of 20 is in table 11.28

At the5%significance level, what can you conclude?

Short Answer

Expert verified

At the 5%significance level, we are unable to reject the null hypothesis. As a result, there is sufficient information to conclude that observed and predicted test scores are identical.

Step by step solution

01

Given Information   

Given tables are

we have to determine what can be concluded at 5%significance level.

02

Explanation  

We know that there are1000total frequencies. As a result, we multiply each frequency by 1000and calculate the table below.

The following steps will be used to calculate the χ2test statistic.

1. In the first column of the excel sheet, we write the expected frequencies.

2. Fill in the first column of the excel sheet with the observed frequencies.

3. Create a column titled (Observed - Expected)

4. Create a new column to calculate the square of the result (Observed Expected)

5. Divide the square of (Observed - Predicted) by the expected frequencies of each observation in the last column.

6. Finally, we add the last two columns together.

Let's now perform the calculation in Excel as follows:

χ2test statistic is ≈2.04≈2.04

The P value can be computed in excel as shown below:

The P value is ≈0.56

therefore, At the 5%significance level, we are unable to reject the null hypothesis. As a result, there is sufficient information to conclude that observed and predicted test scores are identical.

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Most popular questions from this chapter

Use a solution sheet to solve the hypothesis test problem. Go to Appendix E for the chi-square solution sheet. Round expected frequency to two decimal places.

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