/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 91 A major food manufacturer is con... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A major food manufacturer is concerned that the sales for its skinny french fries have been decreasing. As a part of a feasibility study, the company conducts research into the types of fries sold across the country to determine if the type of fries sold is independent of the area of the country. The results of the study are shown in Table 11.48. Conduct a test of independence.

Short Answer

Expert verified

The type of fries sold is dependent of the area of the country.

Step by step solution

01

Step 1. Given information

A major food manufacturer is concerned that the sales for its skinny French fries have been decreasing. As a part of a feasibility study, the company conducts research into types of fries sold across the country to determine if the type of fries sold is independent of the area of the country. The results of the study are shown in Table 11.48.

02

Step 2. Calculation

Type of Fries

Northeast

South

Central

West

Row Total

Skinny fries

70

50

20

25

165

Curly fries

100

60

15

30

205

Steak fries

20

40

10

10

260

Column Total

370

150

45

65

630

The two factors are the type of fries and the area of the country.

\(H_{0}\): The type of fries sold is independent of the area of the country

\(H_{1}\): The type of fries sold is dependent of the area of the country

The expected results and the value of the test statistic are shown in the table.

Observed

Expected

(Obs-Exp)

(Obs-Exp)^2

(Obs-Exp)^2/Exp

70

96.90

-26.90

723.87

7.47

100

120.40

-20.40

416.03

3.46

200

152.70

47.30

2237.44

14.65

50

39.29

10.71

114.80

2.92

60

48.81

11.19

125.23

2.57

40

61.90

-21.90

479.82

7.75

20

11.79

8.21

67.47

5.73

15

14.64

0.36

0.13

0.01

10

26.83

-16.83

283.09

10.55

25

17.02

7.98

63.62

3.74

30

21.15

8.85

78.31

3.70

10

26.83

-16.83

283.09

10.55

73.10

Therefore, value of the test statistic: \(X^{2}=73.10\)

Distribution for the test: \(X^{2}_{6}\)

\(df=(4columns -1)(3rows-1)=3\times 2=6\)

Graph:

Probability statement: p-value\(=P(x^{2}>73.10)=3.1379\times 10^{-11}\)

Compare \(\alpha\) and the p-value: Since no \(\alpha\) is given, assume \(\alpha=0.05\). p-value\(=3.1379\times 10^{-11}\).

Therefore, \(\alpha >p-\)value.

Decision: Since \(\alpha >p-\)value, reject \(H_{0}\). This means that the factors are not independent.

Conclusion: At a \(5%\) level of significance, from the data, there is sufficient evidence to conclude that the type of fries sold and the area of the country are dependent on one another.

The type of fries sold is dependent of the area of the country.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The number of births per woman in China is 1.6down from 5.91in 1966. This fertility rate has been attributed to the law passed in 1979restricting births to one per woman. Suppose that a group of students studied whether or not the standard deviation of births per woman was greater than 0.75. They asked 50women across China the number of births they had had. The results are shown in Table. Does the students’ survey indicate that the standard deviation is greater than 0.75?

# of birthsFrequency0513021035

The manager of "Frenchies" is concerned that patrons are not consistently receiving the same amount of French fries with each order. The chef claims that the standard deviation for a ten-ounce order of fries is at most 1.5oz., but the manager thinks that it may be higher. He randomly weighs49 orders of fries, which yields a mean of 11 oz. and a standard deviation of two oz.

A teacher predict that the distribution of grades on the final exam will be and they are recorded in table 11.27

The actual distribution for a class of 20 is in table 11.28

At the5%significance level, what can you conclude?

When looking at energy consumption, we are often interested in detecting trends over time and how they correlate among different countries. The information in Table 11.57 shows the average energy use (in units of kg of oil equivalent per capita) in the USA and the joint European Union countries (EU) for the six-year period 2005 to 2010. DoW? Perform the analysis at the 5% significance level.

Consumers may be interested in whether the cost of a particular calculator varies from store to store. Based on surveying 43 stores, which yielded a sample mean of \(84 and a sample standard deviation of \)12, test the claim that the standard deviation is greater than $15.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.