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Find the probability that the sum of the 100values is greater than 3,910.

Short Answer

Expert verified

The probability that the sum of the 100 values is greater than 3,910isP(X≥3910)=0.0359.

Step by step solution

01

Given Information

From the information given in the question, the mean is 39.01with a standard deviation of 0.5.

02

Explanation

To find the probability that the sum of the 100values is greater than3910:

∑X~Nnμx,nσx

∑X~N((100)(39.01),(100)(0.5))

P(X≥3910)=PZ≥X-nμxnσx=PZ≥3910-39015=P(Z≥1.8)

P(X≥3910)=0.0359

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