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Find the percentage of sums between 1.5 standard deviations below the mean and one standard deviation above the mean.

Short Answer

Expert verified

MEAN is used to calculate the entire data in statistical terms.

Step by step solution

01

Given information

Explanation:

The sample size of forty is randomly drowned from cholesterol with mean180and standard deviation20. The mean of sums is given as:

∑X=(n)(μX)−(z)(n)(σX)

7326.49

The sum that is1.5the standard deviation below the mean of the 7010.26sum is given as;

ΣX=(n)(μX)−(z)(n)(σX)

7010.26

The percentage for the sums between the standard deviation below the mean of sums and the standard deviation above the mean of the sum is 77.45%.

02

Final answer

The percentage for the given standard deviation is 77.45%.

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Most popular questions from this chapter

The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of \(4.59and a standard deviation of \)0.10. Sixteen gas stations from the Bay Area are randomly chosen. We are interested in the average cost of gasoline for the 16gas stations. The distribution to use for the average cost of gasoline for the 16gas stations is:

a.X¯~N(4.59,0.10)

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d.X¯~N4.59,160.10

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a. The mean, median, and mode are equal.

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c. The curve never touches the x-axis.

d. The curve is skewed to the right.

A uniform distribution has a minimum of six and a maximum of ten. A sample of 50is taken.

Find the 15th percentile for the sums.

Based on data from the National Health Survey, women between the ages of 18and 24have an average systolic blood pressures (in mm Hg) of 114.8with a standard deviation of 13.1. Systolic blood pressure for women between the ages of 18to 24follow a normal distribution.

a. If one woman from this population is randomly selected, find the probability that her systolic blood pressure is greater than 120.

b. If40women from this population are randomly selected, find the probability that their mean systolic blood pressure is greater than 120.

c. If the sample were four women between the ages of18to 24 and we did not know the original distribution, could the central limit theorem be used?

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